<span>expressions for the mean and standard deviation of y if this variable is determined by the expression y
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The distance between two points is calculated through the equation,
d = √(x₂ - x₁)² + (y₂ - y₁)²
Substituting the known values from the given above,
d = √(4 - -4)² + (4 - -4)²
d = 8√2 = 11.31
The distance between the points is approximately equal to 11.31. The value that Jason presented is not the real distance because it does not account for the other set of coordinates.
9514 1404 393
Answer:
5/4
Step-by-step explanation:
The slope can be found using the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (9 -4)/(7 -3) = 5/4
The slope of the line through those points is 5/4.
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The attached graph shows the equation of the line in point-slope form, so you can see that the computed slope makes the line go through both points.
Y-5=m(x+2) is the answer in point slope form
Answer:
B
Step-by-step explanation:
We want to find the point-slope equation of a line that passes through the points (-1, 4) and (8, -2).
Point-slope form is given by:
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
Where <em>m</em> is the slope and (<em>x₁, y₁</em>) is a point.
So, let's find the slope of the line first. We can use the slope formula:
![\displaystyle m=\frac{\Delta y}{\Delta x}=\frac{-2-4}{8-(-1)}=\frac{-6}{9}=-\frac{2}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20m%3D%5Cfrac%7B%5CDelta%20y%7D%7B%5CDelta%20x%7D%3D%5Cfrac%7B-2-4%7D%7B8-%28-1%29%7D%3D%5Cfrac%7B-6%7D%7B9%7D%3D-%5Cfrac%7B2%7D%7B3%7D)
We can choose (-1, 4) as our point. So, (<em>x₁, y₁</em>) = (-1, 4).
Substitute:
![\displaystyle y-(4)=-\frac{2}{3}(x-(-1))](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y-%284%29%3D-%5Cfrac%7B2%7D%7B3%7D%28x-%28-1%29%29)
Simplify:
![\displaystyle y-4=-\frac{2}{3}(x+1)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y-4%3D-%5Cfrac%7B2%7D%7B3%7D%28x%2B1%29)
Therefore, our answer is B.