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Genrish500 [490]
3 years ago
12

PLEASE HELP ME!!

Mathematics
1 answer:
solniwko [45]3 years ago
5 0

Answer:

B) 38.4

Step-by-step explanation:

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Simplify 4y + 2y - 5y
goldfiish [28.3K]

Answer:

Your answer is y.

Step-by-step explanation:

4y+2y-5y         given

=6y-5y             add

=y                    subtract

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Please help if you can.
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C

Step-by-step explanation:

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Mr. Wells to tell his class of 24 that when they have completed the assignment they have may play online games at the end of the
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Answer: 15

Step-by-step explanation:

x         60

___ = ____

24      100

15

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What is 5/6 + 2/5 in its simplest form
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What is the area of a triangle with vertices at (0, – 2), (8, – 2), and (9, 1)?
Luda [366]

<u>ANSWER:  </u>

The area of the triangle with vertices at (0, – 2), (8, – 2), and (9, 1) is 12 square units.

<u>SOLUTION: </u>

Given, vertices of the triangle are A(0, -2), B(8, -2) and C(9, 1).

We have to find the area of the given triangle.

We know that,

\text { Area of triangle }=\frac{1}{2}\left(x_{1}\left(y_{2}-y_{3}\right)+x_{2}\left(y_{3}-y_{1}\right)+x_{3}\left(y_{1}-y_{2}\right)\right)

\text { Where, }\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right),\left(x_{3}, y_{3}\right) \text { are vertices of the triangle. }

Here in our problem, \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)=(0,-2),\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)=(8,-2) \text { and }\left(\mathrm{x}_{3}, \mathrm{y}_{3}\right)=(9,1)

Now, substitute the above values in the formula.

\text { Area of triangle }=\frac{1}{2}\left(x_{1}\left(y_{2}-y_{3}\right)+x_{2}\left(y_{3}-y_{1}\right)+x_{3}\left(y_{1}-y_{2}\right)\right)

=\frac{1}{2}(0(-2-1)+8(1-(-2))+9(-2-(-2))

=\frac{1}{2}(0+8(1+2)+9(2-2))

\frac{1}{2}(0 + 0 +24) = \frac{24}{12} = 2

Hence, the area of the triangle is 12 sq units.

7 0
3 years ago
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