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4 years ago

Distributive property to factor out the greatest common factor

Mathematics

1 answer:

Bingel [31]4 years ago

7 0

Tttttttttttttttttttttttt

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Which is true about the completely simplified difference of the polynomials 6x^6 − x^3 y^4 − 5x y^5 and 4x^5 y + 2x^3 y^4 + 5x y

mr_godi [17]

We know that it is a 7th degree polynomial with 4 terms.

In order to find this, we must first do the subtraction.

6x^6 − x^3 y^4 − 5x y^5 - (4x^5 y + 2x^3 y^4 + 5x y^5)

Then we can simplify using like terms.

6x^6 - 4x^5y - 3x^3y^4 - 10xy^5

You'll see the 4 terms in the final answer. You'll also see that the term with the highest number of variables is -3x^3y^4, which has 3 x's and 4 y's for a total of 7. This makes this a 7th degree polynomial.

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3 years ago

A plane intersecting a double-napped cone is perpendicular to the central axis. Which conic section is formed?

kkurt [141]

A) Circle

Correct on Edge 2021

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3 years ago

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choli [55]

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3 years ago

7 times what equals 77

Flura [38]

11×7=77 thats the answer

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4 years ago

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Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants. 5x − 4 x(x2 + 7

Nikitich [7]

Answer:

$\frac{5x-4}{x(x^2+7)^2} = \frac{A}{x} + \frac{Bx+C}{x^2+7} + \frac{Dx+E}{(x^2+7)^2}$

Step-by-step explanation:

Given the expression $\frac{5x-4}{x(x^2+7)^2}$ , we are to re-write the expression in form of a partial fraction.

Before we write in form of a partial fraction, we need to note the expression at the denominator. Since the expression in parenthesis is a quadratic equation, the equivalent numerator must be a linear expression.

Also the quadratic equation is a repeated form since it is squared. This means that we are to repeat the quadratic equation twice when writing as a partial fraction.

$\frac{5x-4}{x(x^2+7)^2} = \frac{A}{x} + \frac{Bx+C}{x^2+7} + \frac{Dx+E}{(x^2+7)^2}$

From the above partial fraction, it can be seen that x² + 7 in parenthesis was repeated twice and their equivalent expressions at the numerator are both linear i.e Bx+E and Dx+ E where A, B, C, D and E are the unknown constant.

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3 years ago