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IRISSAK [1]
3 years ago
13

Wallace took out a $5,000 loan for six years. He is being charged 4 percent interest, compounded annually. Calculate the total a

mount he will pay.
Mathematics
1 answer:
Shtirlitz [24]3 years ago
8 0
The principal or the present worth is equal to $5000. The time of loan is six years and interest is equal to 0.04. The formula to be followed to get the future worth is F = P *(1+i)^n ; Substituting, the given values,  F = $5000 * (1+0.04)^6 = $6326.60
You might be interested in
In order to solve the system of linear equations, the coefficients of one of the variables must be the same number but opposite
Mashutka [201]

Answer:

Step-by-step explanation:

because both equations do not have matching numbers for the x or y variable, and both equations are positive you are going to have to multiply each equation by a number  so that there will be at least one variable with the same number but with opposite signs.

it does not matter which variable you choose.

lets use y because 2 and 3 are smaller then 2 and 5.

so lets multiply the first equation by 2 in order to get y equal to 6.

2(2x)+2(3y)=(2)6

(do not forget to multiply what the equation is equal to also)

4x+6y=12

now for the second equation we need y to equal negative 6

-3(5x)+-3(2y)=-3(4)

-15x-6y=-12

now lets put the 2 new equations next to each other and see what we can cancel out

4x+6y=12

-15x-6y=-12

-11x=0

x=0

now plug 0 in for x and solve for y (it does not matter which of the 4 equations you choose to solve.

2(0)+3y=6

3y=6

y=2

so your answer is x=0, y=2

8 0
3 years ago
In order to ensure efficient usage of a server, it is necessary to estimate the mean number
juin [17]

Answer:

a. [36.19;39.21]

b. Reject the null hypothesis. The population mean of users that are connected at the same time is greater than 35.

Step-by-step explanation:

Hello!

Your study variable is,

X: "number of users of one server at a time"

The objective is to estimate the mean, for this, a sample of n=100 times was taken and the standard deviation S= 9.2 and the sample mean is X[bar]= 37.7 were calculated.

You need to study the population mean, for this you need your variable to have at least normal distribution. Since you don't have information about its distribution, but the sample is big enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample mean X[bar] to normal:

X[bar]≈N(μ;σ²/n)

a. With this approximation, you can construct the 90% Confidence Interval using the approximate Z

[X[bar] ± Z_{1-\alpha /2} * S/√n]

Z_{1-\alpha /2} = Z_{0.95} = 1.64

[37.7± 1.64* 9.2/√100]

[36.19;39.21]

b. You need to test if the population mean is greater than 35 with a level of significance of 1%.

The hypothesis is:

H₀: μ ≤ 35

H₁: μ > 35

α: 0.01

This is a one-tailed test so you have only one critical level (right tail):

Z_{1\alpha } = Z_{0.99} = 2.33

This means that if the value of the calculated statistic is equal or greater than 2.33 you will reject the null Hypothesis.

If the value is less than 2.33 you will support the null hypothesis.

The statistic is:

Z=<u> X[bar] - μ </u>= <u> 37.7 - 35 </u> = 2.93

       S/√n           9.2/10

The value 2.93 > 2.33, so you reject the null hypothesis. This means that the population mean of users that are connected at the same time is greater than 35.

<u><em>Note: </em></u><em>To make the decision using the interval calculated on a), the hypothesis should have been two-tailed and the confidence and significance levels complementary.</em>

I hope it helps!

7 0
3 years ago
The angle of elevation from the top of a house to a jet flying 2 miles above the house is x radians. If d represents the horizon
alisha [4.7K]

Answer:

d = 2cot(x) or d = 2/tan(x)

Step-by-step explanation:

The vertical distance from the jet to the top of the house represents the opposite side to the 'x' angle, while the horizontal distance, d, represents the adjacent side. Since we do not know the hypotenuse, the tangent and cotangent functions are the preferable choices:

tan (x) = \frac{2}{d}\\d = \frac{2}{tan (x) }\\cot (x) = \frac{d}{2} \\d= 2cot(x)

Therefore, the distance 'd' can be expressed as d = 2cot(x) or d = 2/tan(x).

6 0
3 years ago
Given f(x)=2a^2b+3a^3b^2+2a^2b^4 what is the degree?
lilavasa [31]
We have the following function:
 f (x) = 2a ^ 2b + 3a ^ 3b ^ 2 + 2a ^ 2b ^ 4
 We note that the function depends on x because it is f (x).
 However, there is no variable x in the function.
 Therefore we can assume that the function is constant, since:
 a = constant
 b = constant
 Therefore, the degree of the function is zero
 Answer:
 
The function is zero degree.
7 0
3 years ago
I need help with this question plsss
olga55 [171]

Answer: maybe its 6

Step-by-step explanation:

i think its 6 because it has +3 so maybe adding 3+3

7 0
3 years ago
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