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3 years ago

Help and show work for #9

Mathematics

1 answer:

GuDViN [60]3 years ago

5 0

Answer: 11,304mi^2

We're finding area of a circle.

A = pi*r^2

A = pi*60^2

A = pi*3600

A = 11,304mi^2

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Is xsquare+1/xsquare equal5 is quadratic or not

MAXImum [283]

Answer:

Yes, it is a quadratic equation.

Step-by-step explanation:

Let's solve it to make it a quadratic equation:

=> $\frac{x^2+1}{x^2} =5$

=> x²+1 = 5x²

=> 5x²-x²-1 = 0

=> 4x²-1 = 0

Comparing it with the standard form of quadratic equation i.e.

$ax^2+bx+c = 0$

So, we get

a = 4 , b = 0 and c = -1

So, yes. It is a quadratic equation and it is a pure quadratic equation since b is equal to 0.

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4 years ago

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Ymorist [56]

Answer:

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3 years ago

Complete the proof of this.

VARVARA [1.3K]

Answer:

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3 years ago

A. Student GPAs: Bob’s z-score z = + 1.71 μ = 2.98 σ = 0.36 b. Weekly work hours: Sarah’s z-score z = + 1.18 μ = 21.6 σ = 7.1 c.

hjlf

Answer:

a) $x = \mu +z*\sigma$

And replacing we got:

$x= 2.98 + 1.71*0.36 = 3.5956$

b) $x = \mu +z*\sigma$

And replacing we got:

$x= 21.6 + 1.18*7.1 = 29.978$

c) $x = \mu -z*\sigma$

And replacing we got:

$x= 150 - 1.35*40= 96$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable of interest for this case. We define the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

And for this case we know that $z = 1.71, \mu = 2.98,\sigma = 0.36$

If we solve for x from the z score formula we got:

$x = \mu +z*\sigma$

And replacing we got:

$x= 2.98 + 1.71*0.36 = 3.5956$

Part b

Let X the random variable of interest for this case. We define the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

And for this case we know that $z = 1.18, \mu = 21.6,\sigma = 7.1$

If we solve for x from the z score formula we got:

$x = \mu +z*\sigma$

And replacing we got:

$x= 21.6 + 1.18*7.1 = 29.978$

Part c

Let X the random variable of interest for this case. We define the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

And for this case we know that $z = -1.35, \mu = 150,\sigma = 40$

If we solve for x from the z score formula we got:

$x = \mu -z*\sigma$

And replacing we got:

$x= 150 - 1.35*40= 96$

5 0

3 years ago

The area of a rectangle is 33 ft^2, and the length of the rectangle is 5 ft less than double the width. Find the dimensions of t

dimaraw [331]

Answer:

Length = 6

Width = 5.5

Step-by-step explanation:

Let's use the variable x to represent the width:

x = width

The question says that the length of the rectangle is "5 ft less than double the width". This length can be represented like this:

2x - 5 = length

To find the area of a rectangle, you multiply the width and length, so we are going to write an equation where we multiply the width and length and set it equal to 33 ft^2, which is the area:

(x)(2x - 5) = 33

Now use basic algebra to solve for x:

2x^2 - 5x = 33

2x^2 - 5x - 33 = 0

2x^2 + 6x - 11x - 33 = 0

(2x^2 + 6x) + (-11x - 33) = 0

2x(x + 3) - 11(x + 3) = 0

(2x - 11) (x + 3) = 0

x = 11/2, -3

x either equals 11/2 or -3. However, remember that x represents the width, and you can't have a negative number for a width, so x = 11/2 or 5.5.

Now plug in 5.5 to the length expression and simplify:

2(5.5) - 5

11 - 5 = 6

The length is 6 and the width is 5.5.

Hope this helps (●'◡'●)

7 0

3 years ago