Answer:
The range of T is a subspace of W.
Step-by-step explanation:
we have T:V→W
This is a linear transformation from V to W
we are required to prove that the range of T is a subspace of W
0 is a vector in range , u and v are two vectors in range T
T = T(V) = {T(v)║v∈V}
{w∈W≡v∈V such that T(w) = V}
T(0) = T(0ⁿ)
0 is Zero in V
0ⁿ is zero vector in W
T(V) is not an empty subset of W
w₁, w₂ ∈ T(v)
(v₁, v₂ ∈V)
from here we have that
T(v₁) = w₁
T(v₂) = w₂
t(v₁) + t(v₂) = w₁+w₂
v₁,v₂∈V
v₁+v₂∈V
with a scalar ∝
T(∝v) = ∝T(v)
such that
T(∝v) ∈T(v)
so we have that T(v) is a subspace of W. The range of T is a subspace of W.
X^3 = 216
by taking cubic root for both sides
![\sqrt[3]{x^3} = \sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B3%5D%7B216%7D%20)
x = 6
Answer:
45%
Step-by-step explanation:
Answer:
Option(D)
Step-by-step explanation:
Given are the two triangles, that are ABC and DEF, in which AB=8ft, DE=6ft, AC=10ft and DF=7.5ft.
For the two triangles to be similar, it must satisfy the similarity condition that is:
Both the triangles must have congruent angles and the sides should be proportional. Since, two sides of the given triangles are not proportional.Moreover, ∠A=25° and ∠D=24° which are not equal and ∠C=60° and ∠F=61° which are also not equal.
Therefore, Not all the angles are congruent, thus the triangles cannot be similar.
