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2 years ago

VIEW THE GRAPH WILL MARK BRAINLY IF DONE QUICKlY

Mathematics

2 answers:

Kamila [148]2 years ago

8 0

Answer:

115, 10, (0,10)

Step-by-step explanation:

got it right on Edmentum, Those should fill in the blanks

Gelneren [198K]2 years ago

5 0

Step-by-step explanation:

<h2>The following graph shows the ... ... or not to continue the recent lunch special promotion at his restaurant. ... earned, y, from the number of lunch specials ordered per hour, x.</h2>

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Help please !! easy question i believe :))

kolezko [41]

Solve for x given two sides

Solution

x is an angle hence we are gonna use the formula Sin

Sin 0 = opp/hyp

0 represents theta.

Sin 0 = opp/hyp
Sin 0 = 27/33

Put 27/33 in decimal form

= 0.8181

Transpose to make 0 the subject

Sin 0 = 0.8181

0 = Sin-1 0.8181

When adding Sin from one side to another it becomes Sin inverse.

0 = Sin-1 08181

Now we find the answer

0 = Sin-1 0.8181

= 54.89 degrees

Therefore x is equal to 54.9 to the nearest tenth.

6 0

2 years ago

For z = –2 + 2i, which graph represents z and –2z?

iVinArrow [24]

Answer:

Graph B

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

2. The National Safety Council routinely analyzes the benefit of seat belt use on driver safety. Their data showed that among 28

JulijaS [17]

Answer:

We conclude that there is difference in the proportion of deaths between the 2 groups.

Step-by-step explanation:

We are given that among 2823 drivers not wearing seat belts, 31 died as a result of injuries, and among 7765 drivers wearing seat belts 16 were killed.

Let $p_1$ = proportion of deaths when drivers were not wearing seat belts.

$p_2$ = proportion of deaths when drivers were wearing seat belts.

So, Null Hypothesis, $H_0$ : $p_1=p_2$ {means that there is no difference in the proportion of deaths between the 2 groups}

Alternate Hypothesis, $H_A$ : $p_1\neq p_2$ {means that there is difference in the proportion of deaths between the 2 groups}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of deaths when drivers were not wearing seat belts = $\frac{31}{2823}$ = 0.011

$\hat p_2$ = sample proportion of deaths when drivers were wearing seat belts = $\frac{16}{7765}$ = 0.002

$n_1$ = sample of drivers not wearing seat belts = 2823

$n_2$ = sample of drivers wearing seat belts = 7765

So, the test statistics = $\frac{(0.011-0.002)-(0)}{\sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} } }$

= 4.438

The value of z test statistics is 4.438.

Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is difference in the proportion of deaths between the 2 groups.

Also, Margin of error (E) = $1.96 \times \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} }$