1st = 100% - 20% = 80%
2nd= 100%-15% = 85%
Net Price Factor = 0.8 x 0.85 = 0.68
Net Price = $1899 x 0.68
Final Net Price = $1,291.32
Total Discount= $1899 - 1,291.32 = $607.68
Answer:
16.05% probability of 6 job applications received in a given week.
Step-by-step explanation:
When you have the mean during an interval, you should use the Poisson distribution.
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Records show that the average number of job applications received per week is 5.9.
This means that 
Find the probability of 6 job applications received in a given week.
This is P(X = 6).


16.05% probability of 6 job applications received in a given week.
" the product " means multiply......" the difference " means subtract
the product of 5 and the difference of q minus 5 =
5(q - 5) <== ur expression
MV is the answer. Because AC to VJ as RO is just MV
The first part of the question is not needed
we only need to know M1 and M2
(y2-y1)^2+(x2-x1)^2=(your answer)^2
(5-16)^2+(-3-2)^2=(your answer)^2
(-11)^2+(-5)^2=(your answer)^2
121+25=(your answer)^2
146=(your answer)^2
√146=12.0830459735945721
nearest tenth=12.1