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Viefleur [7K]
3 years ago
12

You measure 22 textbooks' weights, and find they have a mean weight of 64 ounces. Assume the population standard deviation is 5.

1 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight.
Give your answers as decimals, to two places

Mathematics
1 answer:
lara31 [8.8K]3 years ago
3 0

Answer:

Step-by-step explanation:

We want to determine a 90% confidence interval for the true population mean textbook weight.

Number of sample, n = 22

Mean, u = 64 ounces

Standard deviation, s = 5.1 ounces

For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

It becomes

64 ± 1.645 × 5.1/√22

= 64 ± 1.645 × 1.087

= 64 ± 1.788

The lower end of the confidence interval is 64 - 1.788 = 62.21 ounces

The upper end of the confidence interval is 64 + 1.788 = 65.79 ounces

Therefore, with 90% confidence interval, the true population mean textbook weight is between 62.21 ounces and 65.79 ounces

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Nola was selling tickets at the high school dance. At the end of the evening she picked up the cash box and noticed a dollar lyi
Blizzard [7]

Answer:

The $1 belongs to the cash box

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine if the $1 belongs to the cash box or not

Represent singles with s and couples with c.

From the attachment, we have:

s + c = 47 --- total attendance

5s + 4c =200 --- ticket sold

Solve for s and c.

Make s the subject in (1)

s = 47-c

Substitute 47 - c for s in (2)

5(47 - c) + 4c = 200

Open bracket

235 - 5c + 4c = 200

235 - c = 200

c = 235 - 200

c = 35

This means that the total individual which makes up the couples are 35. This is not possible because couples are in 2's and the total should be an even number.

<em>So, we can conclude that the $1 belongs to the cash box</em>

4 0
3 years ago
How much times does it take for the first black/clear part to fall through the photo gate timer, starting from the rest? Plastic
Alik [6]
I can figure out this is a frefall motion.

Starting from rest => Vo = 0

Then, use the equation: d = [1/2]gt^2 => t = √(2d/g)

d = width of a black/clear stripe pair = 5cm = 0.05m

g ≈ 10 m/s^2 (the real value is about 9.81 m/s^2)

t =√(2*0.05m/10m/s^2) =  0.1 s

Answer: approximately 0.1 s
5 0
3 years ago
Jill Kingman pays a $419.00 premium annually. This represents 35% of the total premium. The rest of the premium is paid by her e
Leto [7]

Answer:

I think the answer is 1,466.50

8 0
3 years ago
Ellen is excited to learn how to ski. She went to White Peaks Mountain, rented a pair of skis for $45, and took 4 hours of group
Vikentia [17]

Answer:

x=30h

Step-by-step explanation:

First, you need to figure out how much she actually paid for lessons, so you need to subtract 45 from 165.

165-45=120

Now you know she paid 120 dollars in total for lessons.

You know she took four hours of lessons, so you divide 120 by 4.

120/4=30

It takes $30 an hour for lessons.

Now you can form an equation.

Since you know it takes $30 per hour of lessons, it will be 30h.

x is the full amount of money paid

You don't need to add 165-45 to your equation because not everyone will need to rent skis when they come to White Peaks.

Hope this helps!

6 0
3 years ago
Find the compound Interest for Rs.18,800 ,calculated for 2 years at 13% rate of Interest compounded annually
Vinvika [58]

For compound interest, the formula is given below:

Amount = P(1+\frac{r}{100} )^{n}

Here, P = 18,800

n = 2

r = 13/100

So, Amount = 18,800(1+\frac{13}{100} )^{2}

18,800(1.13)^{2}

= 18,800 × 1.2769

= 24005.72

Compound Interest = Amount - Principal

Compound Interest = 24005.72 - 18800

= 5205.72

Hence, the compound interest for Rs.18,800, calculated for 2 years at 13% rate of interest compounded annually is Rs.5205.72.


4 0
3 years ago
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