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Sav [38]
3 years ago
14

Line segments JK and JL in the xy-coordinate plan both have a common endpoint J(-4,11) and midpoints at M1 (2,16) and M2 (-3,5),

respectively. What is the distance between M1 and M2? Round to the nearest tenth.
Mathematics
1 answer:
OleMash [197]3 years ago
6 0
The first part of the question is not needed 
we only need to know M1 and M2
(y2-y1)^2+(x2-x1)^2=(your answer)^2
(5-16)^2+(-3-2)^2=(your answer)^2
(-11)^2+(-5)^2=(your answer)^2
121+25=(your answer)^2
146=(your answer)^2
√146=12.0830459735945721
nearest tenth=12.1
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Read 2 more answers
1/2 + 5/3 - 1<br>------------------<br> 3/4
Sav [38]
Hey there :)

\frac{ \frac{1}{2}+ \frac{5}{3} -1 }{ \frac{3}{4} }
      ↓ Is the same as
\frac{1}{2} + \frac{5}{3} -1 ÷ \frac{3}{4}

Since it is a division by fraction, we can multiply by what is called the reciprocal
( The attached picture might help you )
( \frac{1}{2} + \frac{5}{3} - 1 ) × \frac{4}{3} 
     ↓ For this part, we need the common denominator, which is 6
\frac{1(3)}{2(3)}+ \frac{5(2)}{32)}  \frac{1(6)}{1(6)} × \frac{4}{3}

\frac{3}{6}+ \frac{10}{6}  - \frac{6}{6} × \frac{4}{3}
\frac{7}{6} × \frac{4}{3}
\frac{14}{9} =  1\frac{5}{9}
  ↑
Your final answer
 

7 0
3 years ago
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