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Sav [38]
3 years ago
14

Line segments JK and JL in the xy-coordinate plan both have a common endpoint J(-4,11) and midpoints at M1 (2,16) and M2 (-3,5),

respectively. What is the distance between M1 and M2? Round to the nearest tenth.
Mathematics
1 answer:
OleMash [197]3 years ago
6 0
The first part of the question is not needed 
we only need to know M1 and M2
(y2-y1)^2+(x2-x1)^2=(your answer)^2
(5-16)^2+(-3-2)^2=(your answer)^2
(-11)^2+(-5)^2=(your answer)^2
121+25=(your answer)^2
146=(your answer)^2
√146=12.0830459735945721
nearest tenth=12.1
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What values of k will make the line containing points (k,3) and (-2,1) parallel to the line through (5, K) and (1,0)
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Answer:

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Step-by-step explanation:

For the lines to be parallel, the lines would need to be the same slope. This means to find the slope of each we would take the difference of the rise over the run.

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using pythagorean inequalities, determine which set of the given three sides produces an acute triangle.
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To solve this problem, you need to use the Phythagorean theorem c^2 is equal to the sum of a^2 and b^2. If a less than or equal to b and b is less than or equal to c or a^2 plus  b^2  is greater than c^2 then it is an acute angle. 
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Recall the original number is xy =     42.
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