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Sav [38]
3 years ago
14

Line segments JK and JL in the xy-coordinate plan both have a common endpoint J(-4,11) and midpoints at M1 (2,16) and M2 (-3,5),

respectively. What is the distance between M1 and M2? Round to the nearest tenth.
Mathematics
1 answer:
OleMash [197]3 years ago
6 0
The first part of the question is not needed 
we only need to know M1 and M2
(y2-y1)^2+(x2-x1)^2=(your answer)^2
(5-16)^2+(-3-2)^2=(your answer)^2
(-11)^2+(-5)^2=(your answer)^2
121+25=(your answer)^2
146=(your answer)^2
√146=12.0830459735945721
nearest tenth=12.1
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-(y + 2) + 8 = 3

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Answer:

Step-by-step explanation:

Yes

Theorem 8.3: If two angles are complementary to the same angle, then these two angles are congruent.

∠A and ∠B are complementary, and ∠C and ∠B are complementary.

Given: ∠A and ∠B are complementary, and ∠C and ∠B are complementary.

Prove: ∠A ~= ∠C.

 Statements Reasons

1. ∠A and ∠B are complementary, and ∠C and ∠B are complementary. Given

2. m∠A + m∠B = 90º , m∠C + m∠B = 90º Definition of complementary

3. m∠A = 90 º - m∠B, m∠C = 90º - m∠B Subtraction property of equality

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BaLLatris [955]
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Answer:

see the explanation

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we have

A(x)=2x+5

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Isolate the variable y

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Let

g(x)=y

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<em>Explanation</em>

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Verify

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