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Karo-lina-s [1.5K]
3 years ago
11

How would I set up an equation for this problem?

Mathematics
1 answer:
mel-nik [20]3 years ago
7 0
It would be 67 for the income

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Everbank Field, home of the Jacksonville Jaguars, is capable of seating 76,867 fans. The revenue for a particular game can be mo
k0ka [10]
The total revenue for the event would the total amount earned from the tickets sold. So if x people attended the event, then there would be $(161x). We must keep in mind though the the maximum seating is 76 876. That means that the maximum revenue that can be earned must not exceed $(161)(76 867) = . Hence we have f(x) = 161x where 0 ≤ x ≤ 76867. From this, we can see that the domain is [0, 76867] while range is [0, 12375587]<span>.</span>
6 0
3 years ago
Number of Tickets Total Cost 1 $2.50 2 ? 3 $7.50 4 ? 5 $12.50 6 $15.00 7 $17.50 Assuming that the cost of tickets follows the sa
Gala2k [10]
2= 5.50 4= 10.50 here is your answer 
7 0
3 years ago
X 1/2 rational exponent
Lesechka [4]

Answer:

Step-by-step explanation:

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7 0
2 years ago
Each calendar will sell for $5 each write an equatio to model the total income for selling calendars
Brrunno [24]
To answer the question above, I let x be the number of calendars sold. You may use any other letter as this is just for representation. The total income generated in selling calendars is calculated by multiplying the number of calendars with the price. That is,
                                   total income = 5x
If we let total income be y, our equation is further simplified into, 
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4 0
3 years ago
Flying to Kimpala with a tail wind a plane averaged 158km/hr. On the return trip the plane only average 112km/hr. While flying b
lora16 [44]

The speed of wind and speed of plane in still air  are  23  and  135 km/h respectively.

<u>Step-by-step explanation:</u>

Let the speed of wind and speed of plane in still air  are  w  and  p km/h respectively.  

The effective speed on onward journey was  

p+w=158  ................(1)

The effective speed on return journey was  

p-w=112 ..............(2)

Adding equation (1) and equation (2) we get,  

⇒ (p+w)+(p-w) = 158+112

⇒ 2p = 270

⇒ p = 135

Putting value of p = 135 in p+w=158 we get:

⇒ p+w=158

⇒ 135+w=158

⇒ w=23

Therefore ,The speed of wind and speed of plane in still air  are  23  and  135 km/h respectively.

3 0
2 years ago
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