The relative frequency for the class with lower class limit 31 is 8.57%.
<h3>How to calculate the frequency?</h3>
It should be noted that the lowrr class frequency is 31 in this case.
Therefore, the relative frequency for the class with lower class limit 31 will be:
= 3/(6+4+4+9+3+9) × 100
= 3/35 × 100
= 8.57%
Therefore, the relative frequency for the class with lower class limit 31 is 8.57%.
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Answer:
the solution to: f(x)=g(x)
is X=4
Explanation:
f(x)=g(x) is X=4 because the curves of f(x) and g(x) intersect at a point which has the abscissa 4.
Answer:
~ <em>50 centimeters of the poster ~</em>
Step-by-step explanation:
Let us plan out our steps, and solve for each:
<em>1. Given the information, let us create a proportionality as such:</em>
<em />
5 = 1 ⇒ x - centimeters of the poster
x 10
<em>2. Now let us cross multiply, and solve through simple algebra for x:</em>
5 * 10 = x,
x =<em> 50 centimeters of the poster </em>
<em></em>
Answer:
Alison wins against Kevin by 0.93 s
Step-by-step explanation:
Alison covers the last 1/4 of the distance in 3 seconds, at a constant acceleration 
, we have the following equation of motion
where s (m) is the total distance, ta = 3 s is the time
Similarly, Kevin overs the last 1/3 of the distance in 4 seconds, at a constant acceleration 
, we have the following equation of motion:
tk = 4 s is the time
Since we can conclude that 
, so Alison would win.
The time it takes for Alison to cover the entire track
The time it takes for Kevin to cover the entire track
So Alison wins against Kevin by 6.93 - 6 = 0.93 s
