FOR THE FIRST PROBLEM:
Differentiating p^2 + 2q^2 = 1100 with respect to time => 2p(dp/dt) + 4q(dq/dt) = 0
<span>dp/dt = -2q/p(dq/dt) </span>
<span>R = pq </span>
<span>dR/dt = p(dq/dt) + q(dp/dt) = -p²/2q(dp/dt) + q(dp/dt) = (2q² - 1100)/2q * (dp/dt) + q(dp/dt) </span>
<span>A = (2q - 550/q)
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Answer:
The two equations are similar because they both end up with the same common value. 0=0 The work you need to show that this is correct will be shown below.
Step-by-step explanation:
2(5m−4)−3(m−5)2=−3m2+40m−83
Add 3m^2 to both sides.
−3m2+40m−83+3m2=−3m2+40m−83+3m2
40m−83=40m−83
Subtract 40m from both sides.
40m−83−40m=40m−83−40m
−83=−83
−83+83=−83+83
0=0
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Answer:hello
Step-by-step explanation:
Answer:
Solve for the input that corresponds to the given output value. (Round answers to three decimal places when appropriate. Enter your answers as a comma-separated list. Note: Even though the question may be completed without the use of technology, the authors intend for you to complete the activity using the technology you will be using.
Step-by-step explanation:
Answer:
86º
Step-by-step explanation:
