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3 years ago

What is the written form of 7.007

Mathematics

2 answers:

Alenkasestr [34]3 years ago

5 0

Seven and seven thousandths.

katrin [286]3 years ago

4 0

The answer is seven and seven thousanths

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Quadrilateral ABCD is a rhombus with an area of 20 square inches.

Ugo [173]

Answer:

area of rhombus =1/2 d1×d2

20=1/2 ×10×d2

d2=4

intersection of diagonal make right angle and cut in equal parts

d1/2=10/2=5

d2/2=4/2=2

use Pythagoras in right angle to bide side

side^2= 5^2 +2^2

side = √29

8 0

2 years ago

What is the 2nd term when -3f^3+9f+6f^4-2 f^2 is arranged in descending order

Pavel [41]

The second term would be -3f^3 because when in descending order it is
6f^4 - 3f^3 - 2f^2 + 9f

3 0

2 years ago

Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

8 0

2 years ago

(Past Due) Need Help

Charra [1.4K]

I would say its the second one.

the student shouldve distributed the 2^3x+3 into 2^3x+9

8 0

2 years ago

If 3x + 8x + 4x = 6x + 63, then what is 5x + 23?

klio [65]

7 0

3 years ago

Read 2 more answers