Answer:
7
Step-by-step explanation:
If you use your mouse or something to cover two of the squares at a time and then make tally marks then you should get 7. I'm not sure if i'm right though, so don't take my answer as the law or something like that.
Answer:
Yes (6,3) is a solution
Step-by-step explanation:
It because both of the lines that are shaded intercepted so it works for both
A² + 4a + 3
(a+3)(a+1) This is the length and the width of the rectangle.
Perimeter = length + length + width + width
P = (a+3) + (a+3) + (a+1) + (a+1)
P = a + a + a + a + 3 + 3 + 1 + 1
P = 4a + 6 + 2
P = 4a + 8
B) 4a + 8
Answer:
-3(r-2)/2
Step-by-step explanation:
r/
2
−
2
r
+
6
−
3
r
/2
−
2
r⋅
2/
2+
6
−
3
r/
2
+
−
2r
⋅
2/
2
+
6
−
3
r
−
2
r
⋅
2
/2
+
6
⋅
2/
2
+
−
3
⋅
2/
2
r
−
2
r
⋅2
+
6⋅
2
−
3
⋅
2
/2
r
−
4
r
+
12
−
6
/2
−3
(
r
−
2
)
/2
Hope that helps! Plz, mark brainiest! :D
Have a great day!
