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slamgirl [31]
3 years ago
7

Can $2 for a bottle of orange juice be expressed as a rate?

Mathematics
1 answer:
sweet [91]3 years ago
8 0
Yes you can. Say you want to buy x amount of bottles. How much would you pay? 2x dollars. So the rate is 2 times the number of bottles. Hope this helps. 
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A total of 12,650 voters completed an online survey that asked if they are going to vote for a certain political canidate in an
Masteriza [31]

Answer:You have roughly the same chance of being called as anyone else living in the United States who has a telephone. This chance, however, is only about 1 in 154,000 for a typical Pew Research Center survey. To obtain that rough estimate, we divide the current adult population of the U.S. (about 235 million) by the typical sample size of our polls (usually around 1,500 people). Telephone numbers for Pew Research Center polls are generated through a process that attempts to give every household in the population a known chance of being included. Of course, if you don’t have a telephone at all (about 2% of households), then you have no chance of being included in our telephone surveys.

Step-by-step explanation:

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The question is on the attachement below and there is a tree diagram with information on it.
mylen [45]

Answer:

56 times

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P(red & red) = 0.5×0.6 = 0.3

Expected no. = no. Of trials × p

No. of trials: 84/0.3 = 280

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= 56

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The caller times at a customer service center has an exponential distribution with an average of 22 seconds. Find the probabilit
jenyasd209 [6]

Answer:

The probability that a randomly selected call time will be less than 30 seconds is 0.7443.

Step-by-step explanation:

We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.

Let X = caller times at a customer service center

The probability distribution (pdf) of the exponential distribution is given by;

f(x) = \lambda e^{-\lambda x} ; x > 0

Here, \lambda = exponential parameter

Now, the mean of the exponential distribution is given by;

Mean =  \frac{1}{\lambda}  

So,  22=\frac{1}{\lambda}  ⇒ \lambda=\frac{1}{22}

SO, X ~ Exp(\lambda=\frac{1}{22})  

To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;

    P(X\leq x) = 1 - e^{-\lambda x}  ; x > 0

Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)

        P(X < 30)  =  1 - e^{-\frac{1}{22} \times 30}

                         =  1 - 0.2557

                         =  0.7443

7 0
3 years ago
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