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3 years ago

2.04 times 10 negative 6 in standard form

2 answers:

4 0

.00000204 When the exponent is negative, move the decimal that many spaces left. When positive, move the decimal that many spaces to the right.

Sveta_85 [38]3 years ago

3 0

-20.4 in standard form.

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The Russian ice breaker yamal can move forward through 2.3-meter-thick ice at a speed of 5.5 kilometers per hour. Write and solv

aleksandrvk [35]

82.5 / 5.5 = 15

15 hrs.

i think that should be the answer but i didn't use the 2.3 -meter-thick clue...

8 0

3 years ago

Question 9 (1 point)

Romashka [77]

Answer:

Step-by-step explanation:

League A League B

151.12 163.25

148 157

26.83 24.93

29 136

136 145

167 178

207 256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(82.5-1.5\times 76.56,159.06+1.5\times 76.56)$

(-32.34,273.9)

So, There is no outlier

Maximum = 207

League B in ascending order :

24.93,136,145,157,163.25,178,256

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

$Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5$

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(140.5-1.5\times 30.125,170.625+1.5\times 30.125)$

(95.3125,215.8125)

24.93 and 256 are outliers

Maximum = 256

5 0

3 years ago

Factor this polynomial expression.

zloy xaker [14]

Answer:

Step-by-step explanation:

To factor x^2+8x+16, you have to find two numbers that add up to 8 and multiply to your constant, 16. 4 and 4 fit these requirements so you can factor them as (x+4)(x+4). Hope I explained it okay :)

5 0

3 years ago

Read 2 more answers

What are the coordinates of the vertices of the figure A'B'C'after the following transformation. (x,y) ---> ( y, -x)

topjm [15]

9514 1404 393

Answer:

A'(4, 4)
B'(4, 2)
C'(1, 2)

Step-by-step explanation:

Using the transformation ...

(x,y) ⇒ (y, -x) . . . . . . rotation 90° CW

we have ...

A(-4, 4) ⇒ A'(4, 4)

B(-2, 4) ⇒ B'(4, 2)

C( -2, 1) ⇒ C'(1, 2)

5 0

3 years ago

What is the solution to the inequality?

Lilit [14]

The answer would be x>-3

6 0

3 years ago