Answer:
a. 81 square inches
b. 108 inches
Step-by-step explanation:
The area of all 5 squares combined is 405 square inches. This is 5 times the area of 1 square. 405/5 = 81. The area of 1 square is 81 square inches.
Since this is a square, the sides are equal. Thankfully the area of 1 square is a perfect square so the length of one side of the square is a full number, which is 9. All of the squares are congruent as shown in the diagram so we simply add every length together (there are 12 sides, each side is 9 inches).
12*9 = 108 and that is the perimeter.
Answer:
7 in.
Step-by-step explanation:
2L + 2W = 16
Try L = 7
2(7) + 2W = 16
14 + 2W = 16
2W = 2
W = 1
If the length is 7 in., then the width is 1 in. That is perfectly acceptable, so L = 7 in. is a good value.
Try L = 8
2(8) + 2W = 16
16 + 2W = 16
2W = 0
W = 0
A length of 8 would make a width of 0. You can't have a rectangle with 0 width, so L = 8 does not work.
When L = 9 or L = 10, the width would be negative. The width of a rectangle cannot be a negative number, so these values doe not work.
Answer: 7 in.
Answer:
2.) 7.8
Step-by-step explanation:
We can use Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
5^2 + 6^2 = c^2
25+36 = c^2
61 = c^2
Take the square root of each side
sqrt(61) = sqrt(c^2)
7.810249676 = c
Complete question is;
The function f(x) = (25000 + 280x)/x models the average cost per unit, f(x), for Electrostuff to manufacture x units of Electrogadget IV. How many units must the company produce to have an average cost per unit of $390?
Answer:
227 units
Step-by-step explanation:
We are given the function;
f(x) = (25000 + 280x)/x
Where;
f(x) is the average cost per unit
x is the number of units
Now, we want to find out how many units the company must produce to have an average cost per unit of $390.
Thus, plugging $390 for f(x), we have;
390 = (25000 + 280x)/x
When we cross multiply, we get;
390x = 25000 + 280x
390x - 280x = 25000
110x = 25000
x = 25000/110
x ≈ 227
Answer:
200.4 at 0.25%
Step-by-step explanation:
Given data
P= P200
r= 0.25%
t= 1 year
n= 12
A= P(1+ r/n)^nt
substitute
A= 200(1+ 0.0025/12)^12*1
A= 200(1+ 0.00020833333)^12
A= 200(1.0002)^12
A= 200* 1.002
A= 200.4
Hence the amount is 200.4 at 0.25%