The values of x that will give the quadratic equation no real number solutions are -5 and 9
<h3>What are real roots of a quadratic equation?</h3>
Real roots of a quadratic equation are values of x, whose numbers can be represented on a number line.
Analysis:
We have - +3x +c = 0
- 4ac is called the discriminant of a quadratic equation.
if - 4ac < 0, then the quadratic equation has no real root.
where a = -1, b = 3 c = c
-4(-1)c < 0
9 + 4c < 0
4c < -9
c < -9/2
Which means values lower than -9/2 would give the solution no real root.
From, the options, only -5 would give no real solution, since it is lower than -9/2.
Learn more about real roots of a quadratic equation: brainly.com/question/7784687
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Answer:
Step-by-step explanation:
1. cannot be determined. We don't have all the numbers so you can't find the mean (average).
2. True. The median is the line in the middle of the box. The median for movie 1 is greater than 600 and the median for movie 2 is less than 600.
3. True. Interquartile range is the biggest number of the box minus the smallest number of the box. Movie 1 is approximately 200 and movie 2 is approximately 70.
4. True. Q3 is the last line of the box.
Answer:
x= - 7/2
Step-by-step explanation:
Decimal Form: -3.5
Mixed Number Form: -3 1/2
Answer:
C.
Step-by-step explanation:
The answer should be less than 15 for x since its the smallest side and C is the only answer that has that.