All categories

4 years ago

16.1 is what percent of 70

2 answers:

6 0

We can use proportion to solve this problem.
70 ---------- 100% We know that 70 is 100%
16.1 -------- x
Cross multiplying now

$x= \frac{16.1*100}{70}=23%$ - its the result

Dimas [21]4 years ago

6 0

The answer is 23percent

You might be interested in

Angle. How many sides does the polygon have?

tia_tia [17]

The measures of the four angles of quadrilateral ABCD are 36°, 72°, 108° and 144°

<u>Explanation:</u>

A polygon has three or more sides.

Example:

Triangle has 3 sides

Square has 4 sides

Pentagon has 5 sides and so on.

27)

In a quadrilateral ABCD, the measure of ZA, ZB, ZC and ZD are the ratio 1 : 2 : 3 : 4

We know,

sum of all the interior angles of a quadrilateral is 360°

So,

x + 2x + 3x + 4x = 360°

10x = 360°

x = 36°

Thus, the measure of four angles would be:

x = 36°

2x = 2 X 36° = 72°

3x = 3 X 36° = 108°

4x = 4 X 36° = 144°

Therefore, the measures of the four angles of quadrilateral ABCD are 36°, 72°, 108° and 144°

5 0

3 years ago

Helpppppppppp give bralienst

alina1380 [7]

Answer:

Hope that helps.

6 0

3 years ago

Read 2 more answers

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

$\frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

$- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$

Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

$cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}})$

$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

$\implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6})$

$$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

From the above obtained values this can be calculated and the value is $- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ .

3 0

3 years ago

Find the number of real number solutions for the equation.

UkoKoshka [18]

X² - 4x + 4 = 0
(x-2)(x-2) = 0
the equation has one root mainly 2 with multiplicity 2
the answer is a

4 0

3 years ago

At a small college somewhere on the East coast, 20% of the girls and 30% of the boys smoke at least once a week.

Nezavi [6.7K]

Answer: Required mean would be 15.

Step-by-step explanation:

Since we have given that

Number of girls G= 75

Number of boys B= 100

Probability that girls smoke = P₂ = 0.20

Probability that girls don't smoke = P'₂=1-0.20=0.80

Probability that boys smoke = P₁ = 0.30

Probability that boys don't smoke = P'₁=1-0.30=0.70

We need to find the mean of the sampling distribution of the difference in the sample proportion of girl smokers and boys smokers.

So, it becomes,

$E[P_1-P_2]=E[P_1]-E[P_2]\\\\=B\times P_1-G\times P_2\\\\=100\times 0.30-75\times 0.20\\\\=30-15\\\\=15$

Hence, required mean would be 15.

6 0

3 years ago