The lottery's anticipated worth is $80.
Given that,
The probability of receiving $125 is 0.25; the likelihood of receiving $100 is 0.3; and the likelihood of receiving $50 is 0.45.
A) EV=125*.2+100*.3+50*.5=$80
The lottery's anticipated worth is $80.
The expected value is obtained by multiplying each result by its likelihood.
The expected value of the lottery is then calculated by adding up all of these.
This is what we have: ;;
125(0.2) + 100(0.3) + 50(0.5) (0.5)
= 25 + 30 + 25 = $80
B) This is the formula for variance is shown in figure :
So, we can calculate the variance as follows:
.2*(125-80)^2+.3*(100-80)^2+.5*(50-80)^2=975
C) A risk-neutral person would pay $80 or less to play the lottery.
To learn more about probability click here:
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Answer:
how to answer it where is the direction
Answer:
The degrees of freedom are given by:

The p value for this case would be given by:
Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes
Step-by-step explanation:
Information given
represent the sample size
represent the confidence level
represent the sample variance
represent the value that we want to verify
System of hypothesis
We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:
Null Hypothesis:
Alternative hypothesis:
The statistic is given by:
And replacing we got:
The degrees of freedom are given by:

The p value for this case would be given by:
Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes
<u>(83.9 × 10^12)(2.87 × 10^-³)</u>
3.76 × 10²
<u>(83,900,000,000,000)(0.00287)</u>
376
<u>240,793,000,000</u>
376
640,406,914.9
1.12 2.60 hope this helps if it is wrong then I’m sorry