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iogann1982 [59]
3 years ago
12

investment historically have doubled every 9 years if you start with $2000 investment how much money would you have after 45 yea

rs
Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
5 0
First you would divide 45 by 9 to see how many times it will double which gives you 5. Then, you would multiply 2000 by 2^5 (or just 2000x2x2x2x2x2) to get $64000
lisov135 [29]3 years ago
4 0

Answer: $64000

Step-by-step explanation:

The exponential equation for growth in function with growth factor 'b'in time 't' is given by :-

y=Ab^x , where A is the initial value.

Given : The initial value : A=\$2000

Growth rate = b=2\text{ every 9 years}

Time periods in 45 years :t=\dfrac{45}{9}=5

Then , the exponential equation for growth for t=5 is given by :-

y=2000(2)^{5}=64000

Hence, the money you would have after 45 years = $64000

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