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iogann1982 [59]
4 years ago
12

investment historically have doubled every 9 years if you start with $2000 investment how much money would you have after 45 yea

rs
Mathematics
2 answers:
Oksi-84 [34.3K]4 years ago
5 0
First you would divide 45 by 9 to see how many times it will double which gives you 5. Then, you would multiply 2000 by 2^5 (or just 2000x2x2x2x2x2) to get $64000
lisov135 [29]4 years ago
4 0

Answer: $64000

Step-by-step explanation:

The exponential equation for growth in function with growth factor 'b'in time 't' is given by :-

y=Ab^x , where A is the initial value.

Given : The initial value : A=\$2000

Growth rate = b=2\text{ every 9 years}

Time periods in 45 years :t=\dfrac{45}{9}=5

Then , the exponential equation for growth for t=5 is given by :-

y=2000(2)^{5}=64000

Hence, the money you would have after 45 years = $64000

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<h3>Given</h3>

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<h3>Find</h3>

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<h3>Solution</h3>

First of all, look at how this is evaluated in terms of what happens to a value for s.

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To solve for s, you undo these operations in reverse order. The "undo" for addition is adding the opposite. The "undo" for multiplication is division (or multiplication by the reciprocal).

... P = 3r + 2s . . . . . . starting equation

... P - 3r = 2s . . . . . . -3r is added to both sides to undo addition of 3r

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Note that the division is of everything on both sides of the equation. That is why we need to add parentheses around the expression that was on the left—so the whole thing gets divided by 2.

Your solution is ...

... s = (P - 3r)/2

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