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Andrej [43]
3 years ago
11

Two snails in the same class must also be in the same

Biology
1 answer:
Anuta_ua [19.1K]3 years ago
8 0
I think the answer is b as in boy.
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A man is brachydactylous (very short fingers; rare autosomal dominant), and his wife is not. Both can taste the chemical phenylt
netineya [11]

Answer:

The correct answer is -

A) BbTt x bbTt

B) .5^4 or 1/16 or 0.0625

Explanation:

As it is given that Brachydactylus and PTC tasters both traits are autosomal dominant conditions which mean only one allele would be enough.

For Branchydactylus and For tasting :  man and women will be heterogeneous.

Hence,

The Genotype of man = BbTt

The Genotype of wife = bbTt

b. Answer = 0.0625

For Branchydactylus:

Bb X bb

Possible genotypes:

B b

b Bb( Brachydactylus) bb(normal)

b Bb (Brachydactylus) bb (normal)

The probability of a single child being Branchydactylus = 2/4 = 0.5

So,  Probability of all 4 child being Branchydactylus = .5 x .5 x .5 x .5 = 0.0625

3 0
2 years ago
Witch of these is the correct answer? Brainliest Awarded......
Cerrena [4.2K]
B is the correct answer!
3 0
3 years ago
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