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goldenfox [79]
4 years ago
8

A 5000N block is lifted 1000cm. How much work was done?​

Physics
1 answer:
kaheart [24]4 years ago
6 0

Answer:

W(mg) = -5000j

Explanation:

Work done by weight force is = - mgh ==>mg = w & 1000cm = 1m ==> -5000 (1)= -5000j

it is what I can calculate for this question

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zysi [14]

Answer: 2.5

Explanation:

4 0
3 years ago
What were the quartering acts
Phantasy [73]
DescriptionThe Quartering Acts were two or more Acts of British Parliament requiring local governments of the American colonies to provide the British soldiers with housing and food. Each of the Quartering Acts was an amendment to the Mutiny Act and required annual renewal by Parliament.

Hope this helps
7 0
3 years ago
Read 2 more answers
The distance between Earth and Mars is 225 million km. When converted using the conversion factor 1 AU = 1.5 × 108 km, the dista
SIZIF [17.4K]
I guess the problem is asking for the distance between Earth and Mars in Astronomical Units (AU).

Since 1 AU = 1.5 \cdot 10^8 km
and the distance between the two planets is
d=225 mil. km= 2.25 \cdot 10^8 km
we can convert this distance into AU by using the following proportion:
1 AU : 1.5 \cdot 10^8 km = x : 2.25 \cdot 10^8 km

from which we find
x= \frac{1 AU \cdot 2.25 \cdot 10^8 km}{1.5 \cdot 10^8 km} =1.5 AU
7 0
3 years ago
Read 2 more answers
Age, height, and weight are examples of numerical data.
Andrej [43]

Answer:

True

Explanation:

Examples of numerical data are height, weight, age

7 0
2 years ago
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What is the critical angle for the interface between water and light flint? nflint= 1.58, nwater=1.33?
Angelina_Jolie [31]
When light crosses the interface between a medium with higher refractive index and a medium with lower refractive index, there is a maximum value of the angle of incidence after which there is no refraction, but all the light is reflected, and this maximum value is called critical angle.

The critical angle is given by
\theta_C = \arcsin ( \frac{n_2}{n_1} )
where n1 is the refractive index of the first medium while n2 is the refractive index of the second medium. In our problem, n1=1.33 and n2=1.58, so the critical angle is
\theta_C = \arcsin ( \frac{1.33}{1.58} )=57.3 ^{\circ}

3 0
3 years ago
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