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goldenfox [79]
4 years ago
8

A 5000N block is lifted 1000cm. How much work was done?​

Physics
1 answer:
kaheart [24]4 years ago
6 0

Answer:

W(mg) = -5000j

Explanation:

Work done by weight force is = - mgh ==>mg = w & 1000cm = 1m ==> -5000 (1)= -5000j

it is what I can calculate for this question

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C) refract

Explanation:

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In normal space, light travels along a straight path with no alteration of the path along which it travels.

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3 years ago
Two rings of radius 5 cm are 20 cm apart and concentric with a common horizontal x-axis. The ring on the left carries a uniforml
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Answer:

The electric field due to the right ring at a location midway between the two rings is 2.41\times10^{3}\ V/m

Explanation:

Given that,

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E=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{qx}{(x^2+R^2)^{\frac{3}{2}}}

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E=\dfrac{9\times10^{9}\times30\times10^{-9}\times0.1}{((0.1)^2+(0.2)^2)^{\frac{3}{2}}}

E=2.41\times10^{3}\ V/m

Hence, The electric field due to the right ring at a location midway between the two rings is 2.41\times10^{3}\ V/m

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