F(2)=4(2)-3=5
f(6)=4(6)-3=21
1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2
Answer:
1)0.1cm
2)0.05cm
3)1.65cm
4)1.75cm
Step-by-step explanation:
G/L=1000*g/mL, since 1 mL = 1/1000 of a litre.
<span>Therefore, 150g/L=150 000 g/mL.</span>
Answer:
119 R5
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