Ask question

Ask question

All categories

3 years ago

7

What is the solution to this system of linear equations 3x-2y=14 5x+y=32 brainly

2 answers:

den301095 [7]3 years ago

8 0

$3x-2y=14\\5x+y=32$

Multiply 2 in the 5x+y=32 so that we can eliminate the "y"

$3x-2y=14\\5x(2)+(2)y=32(2)$

From 5x(2)+(2)y=32(2), $10x+2y=64$

$3x-2y=14\\10x+2y=64$

Then start eliminating the y,

$13x=78$ [3x+10x = 13x] [-2y+2y = 0] [14+64 = 78]

$x=\frac{78}{13}$

Therefore, $x=6$ but we are not done yet, we need to find the value of y.

Substitute x = 6 in any equations but only one equation so I'll substitute in 5x+y=32 instead.

$5(6)+y=32\\30+y=32\\y=32-30\\y=2$

Therefore, y = 2.

So the answer is x = 6, y = 2 or (6,2)

xxTIMURxx [149]3 years ago

7 0

Answer:

x = 6

y = 2

Step-by-step explanation:

You might be interested in

Which fraction is larger 10/13 or 11/14

dem82 [27]

10/13 would be the larger number and here is why

10/13

10/13 x 3780/3780

37800/49140

so your answer is 10/13

5 0

3 years ago

Read 2 more answers

Which is the solution to the equation 8.25 + 1/4 W = 10.75? Round to the nearest hundredth if necessary.

murzikaleks [220]

$8.25+\dfrac{1}{4}w=10.75\ \ \ \ |-8.25\\\\\dfrac{1}{4}w=2.5\ \ \ |\cdot4\\\\w=10$

3 0

3 years ago

For any positive integer n, prove that n^3-n is divisible by 6.please answer

ikadub [295]

Answer:

yes it is true

Step-by-step explanation:

if we take n=2 then

2°3-2=8-2=6

3 0

2 years ago

Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

3 years ago

Consider randomly selecting a single individual and having that person test drive 3 different vehicles. Define events A1, A2, an

zmey [24]

a. Use the inclusion/exclusion principle.

$P(A_1\cap A_2)=P(A_1)+P(A_2)-P(A_1\cup A_2)=0.55+0.65-0.80=0.40$

b. By definition of conditional probability,

$P(A_2\mid A_3)=\dfrac{P(A_2\cap A_3)}{P(A_3)}=\dfrac{0.50}{0.70}\approx0.7143$

4 0

3 years ago