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Reptile [31]
3 years ago
7

What is the solution to this system of linear equations 3x-2y=14 5x+y=32 brainly

Mathematics
2 answers:
den301095 [7]3 years ago
8 0

3x-2y=14\\5x+y=32

Multiply 2 in the 5x+y=32 so that we can eliminate the "y"

3x-2y=14\\5x(2)+(2)y=32(2)

From 5x(2)+(2)y=32(2), 10x+2y=64

3x-2y=14\\10x+2y=64

Then start eliminating the y,

13x=78 [3x+10x = 13x] [-2y+2y = 0] [14+64 = 78]

x=\frac{78}{13}

Therefore, x=6 but we are not done yet, we need to find the value of y.

Substitute x = 6 in any equations but only one equation so I'll substitute in 5x+y=32 instead.

5(6)+y=32\\30+y=32\\y=32-30\\y=2

Therefore, y = 2.

So the answer is x = 6, y = 2 or (6,2)

xxTIMURxx [149]3 years ago
7 0

Answer:

x = 6

y = 2

Step-by-step explanation:

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Consider the reduction of the complex figure with a scale factor of 1
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URGENT NEED HELP CLICK TO SEE
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D

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