Answer:
m+6n
Step-by-step explanation:
Let number of men who attended last year=m
Let number of women who attended last year=n
This year, we expect Six times the amount of women attendance last year =6 X n = 6n
The same number of men, m will be expected this year
Therefore, Number of Expected Attendees
= Number of Men + (Six Times the Number of Women)
=m+6n
We can expect (m+6n) people to be in attendance this year.
Consider the equation
1) First row of the table
Set x=0 and solve as follows:
The answer is y=20 and the pair x-y is (0,20)
2) Second row
Set x=1 and solve, as follows:
The answers are y=10 and (1,10)
3) Third row.
Set y=0 and solve as follows:
The answers are x=2 and (2,0)
Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
Hello!
First you can distribute the 3
4 + 6r + 6s + 3r
Then you combine like terms
4 + 9r + 6s
The answer is 9r + 6s + 4
Hope this helps!
Answer:
y = 8
Step-by-step explanation:
The equation of a line parallel to the x- axis has equation
y = c
where c is the value of the y- coordinates the line passes through.
Then
y = 8 ← is equation of line parallel to the x- axis
