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ivann1987 [24]
3 years ago
7

Graph the image of this figure after a dilation with a scale factor of 1/2 centered at the point (-3,0)

Mathematics
1 answer:
VladimirAG [237]3 years ago
4 0

Answer:

See image for answer

Step-by-step explanation:

I drew lines connecting the center of dilation and the points. Then, I divided the x-coordinate and the y-coordinate by 2 and I got the point. I did the same thing for the rest of the points and then connected them into a triangle.

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John's bank notified him that he had a negative checking account balance of -$125.70. If John makes two deposits of $89.32 each,
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3 years ago
On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 3, 1) and (0, 3). Everything to th
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The linear equality represented by the graph as,\rm y > \frac{2}{3} x+3

<h3>What is the definition of inequality?</h3>

Inequality is a sort of equation in which the equal sign is missing. As we will see, inequality is defined as a statement regarding the relative magnitude of two claims.

The slope of the dashed line is found as;

\rm m = \frac{y_2-y_1}{x_2-x_1}  \\\\\ m = \frac{3-1}{0+3} \\\\ m= \frac{2}{3}

The slope-intercept form is;

y=mx+c

Substitute the obtained value;

\rm  y = \frac{2}{3}x+3

We are aware that the given line Is a dashed line, and everything to its left is shadowed.

Hence, the linear equality is represented by the graph as,\rm y > \frac{2}{3} x+3

To learn more about inequity, refer to brainly.com/question/20383699

#SPJ1

4 0
2 years ago
The function H(t) = −16t2 + 75t + 25 shows the height H(t), in feet, of a baseball after t seconds. Part A: After how many secon
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Step-by-step explanation:

Given that,

The function that shows the height of a baseball after t seconds is given by :

H(t)=-16t^2+75t+25 ....(1)

Part (A).

When the baseball hits the ground,

H(t) = 0

So,

-16t^2+75t+25=0\\\\t=5\ s\ and\ t=-0.31\ s

After 5 seconds the baseball will hit the ground.

Pat (B)

For maximum height, put dH/dt = 0

So,

\dfrac{d}{dt}(-16t^2+75t+25)=0\\\\-32t+75=0\\\\t=2.34\ s

Put t = 2.34 s in equation (1).

H(t)=-16(2.34)^2+75(2.34)+25\\\\H(t)=112.89\ m

Hence, this is the required solution.

8 0
3 years ago
15 trucks can carry 26,850 kg weight. Find the weight carried by one truck.
nadya68 [22]

\huge\underline{\underline{\boxed{\color{blueviolet}{ANSWER}}}}

★ 15 trucks can carry 26,850 kg weight

★ We've to find the weight carried by one truck

\huge \pink {\overline{ \quad \quad \quad \quad \quad \quad \quad\quad \quad}}

\sf{Number  \: of \:  trucks = 15 }

\sf{Weight  \: carried  \: by  \: one \:  truck = \frac{26,850Kg}{15} }

\sf  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:                  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:= 1790Kg

Therefore , the weight carried by one truck is 1790 kg

7 0
2 years ago
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