Will graphs for these equations show parallel lines? Explain. y=6x+1 y=6x-5

1 answer:

7 0

Yes these lines are parallel. They will never cross so there are no solutions to this system.

The reason why is because the two slopes for the equations are both 6 each. The equations are in y = mx+b form where m is the slope. The y intercepts are different (1 for the first; -5 for the second). So those two pieces of info lead to non-intersecting parallel lines.

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Anton [14]

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163,750 + d = 229,600.

Solve for d to find your answer.

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aliya0001 [1]

Answer:

$f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}$

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

$f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...$

We first compute the n-th derivative of $f(x)=\ln(1+2x)$ , note that

$f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\$

Now, if we compute the n-th derivative at 0 we get

$f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!$

and so the Maclaurin series for f(x)=ln(1+2x) is given by

$f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2 \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}$

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kotykmax [81]

Let the speed of the boat be x
so going against the current the speed is x-7
going with the current the speed is x+7

let the distance be d
time = distance / speed
time to go against the current = d/(x-7)
time to go with the current = d/(x+7)

time going against the current is 3 times going <span>with the current
</span>
d/(x-7) = 3d/(x+7) ⇒⇒⇒ divide by d
1/(x-7) = 3/(x+7)
x+7 = 3(x-7)
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So, the speed of the boat in still water is = 14 mph

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garri49 [273]

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vodka [1.7K]

Answer:

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