They are both liquid measurements
Answer:
A two-digit number can be written as:
a*10 + b*1
Where a and b are single-digit numbers, and a ≠ 0.
We know that:
"The sum of a two-digit number and the number obtained by interchanging the digits is 132."
then:
a*10 + b*1 + (b*10 + a*1) = 132
And we also know that the digits differ by 2.
then:
a = b + 2
or
a = b - 2
So let's solve this:
We start with the equation:
a*10 + b*1 + (b*10 + a*1) = 132
(a*10 + a) + (b*10 + b) = 132
a*11 + b*11 = 132
(a + b)*11 = 132
(a + b) = 132/11 = 12
Then:
a + b = 12
And remember that:
a = b + 2
or
a = b - 2
Then if we select the first one, we get:
a + b = 12
(b + 2) + b = 12
2*b + 2 = 12
2*b = 12 -2 = 10
b = 10/2 = 5
b = 5
then a = b + 2= 5 + 2 = 7
The number is 75.
And if we selected:
a = b - 2, we would get the number 57.
Both are valid solutions because we are changing the order of the digits, so is the same:
75 + 57
than
57 + 75.
Answer:
A. y=2
x+y=2.5
b. x=2 or 5
y=2 or 5
I don't know which on equals 2 and which equals 5, but 5 and 2 are the answers
Step-by-step explanation:
a. 2x0.5=1
b. 2+5=7 and 2x5=10
Answer:
(c) 2
Step-by-step explanation:
2(x - 4) + 7 = 3
2x + 2(-4) + 7 = 3
2x - 8 + 7 = 3
2x - 1 = 3
2x - 1 + 1 = 3 + 1
2x = 4
2x/2 = 4/2
x = 2
Hope this helps!!!
Answer:
I want to stand on my own three feet
Step-by-step explanation: