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postnew [5]
3 years ago
6

Find the value of the variable

Mathematics
1 answer:
WINSTONCH [101]3 years ago
3 0
Which variable are you talking about? In this question x is 4 and y is 5.

Hope this helped!

Good Luck!
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Help ASAP I need to get this question correct
strojnjashka [21]

Answer: The answer is NO

Step-by-step explanation:

8 0
3 years ago
When an automobile is stopped with a roving safety patrol,each tire is checked for tire wear, and each headlight is checkedto se
ryzh [129]

Answer:

a) Joint ptobability distribution

\begin{pmatrix}  &Y=0&Y=1&Y=2&Y=3&Y=4\\X=0&0.3&0.05&0.025&0.025&0.1\\ X=1&0.18&0.03&0.015&0.015&0.06 \\ X=2&0.12&0.02&0.01&0.01&0.04\end{pmatrix}

b) P(X<= 1 and Y <= 1) = P(X<= 1) * P(Y<=1) = 0.56

c) P(X + Y = 0)=0.3

d) P(X + Y <= 1)=0.53

Step-by-step explanation:

We have to construct the joint probability table with the marginal probabilities of X and Y.

X can take values from 0 to 2, and Y can take values from 0 to 4.

We can calculate each point of the joint probability as:

P(x,y)=P_x(x)*P_y(y)

Then, the joint probabilities are:

X=0 Y=0 Px=0.5 Px=0.6 P(0,0)=0.3

X=0 Y=1 Px=0.5 Px=0.1 P(0,1)=0.05

X=0 Y=2 Px=0.5 Px=0.05 P(0,2)=0.025

X=0 Y=3 Px=0.5 Px=0.05 P(0,3)=0.025

X=0 Y=4 Px=0.5 Px=0.2 P(0,4)=0.1

X=1 Y=0 Px=0.3 Px=0.6 P(1,0)=0.18

X=1 Y=1 Px=0.3 Px=0.1 P(1,1)=0.03

X=1 Y=2 Px=0.3 Px=0.05 P(1,2)=0.015

X=1 Y=3 Px=0.3 Px=0.05 P(1,3)=0.015

X=1 Y=4 Px=0.3 Px=0.2 P(1,4)=0.06

X=2 Y=0 Px=0.2 Px=0.6 P(2,0)=0.12

X=2 Y=1 Px=0.2 Px=0.1 P(2,1)=0.02

X=2 Y=2 Px=0.2 Px=0.05 P(2,2)=0.01

X=2 Y=3 Px=0.2 Px=0.05 P(2,3)=0.01

X=2 Y=4 Px=0.2 Px=0.2 P(2,4)=0.04

We can write it in the form of a matrix:

\begin{pmatrix}  &Y=0&Y=1&Y=2&Y=3&Y=4\\X=0&0.3&0.05&0.025&0.025&0.1\\ X=1&0.18&0.03&0.015&0.015&0.06 \\ X=2&0.12&0.02&0.01&0.01&0.04\end{pmatrix}

b) From the joint probability P(X<= 1 and Y <= 1) is equal to

P(X\leq 1 \& Y \leq 1)=P(0,0)+P(0,1)+P(1,0)+P(1,1)\\\\P(X\leq 1 \& Y \leq 1)=0.3+0.05+0.18+0.03=0.56

We can calculate P(X<= 1) * P(Y<=1)

P_x(X\leq 1)=P_x(0)+P_x(1)=0.5+0.3=0.8\\\\P_y(Y\leq1)=P_y(0)+P_y(1)=0.6+0.1=0.7\\\\P_x(X\leq1)*P_y(Y\leq1)=0.8*0.7=0.56

Both calculations give the same result.

c) Probability of no violations

P(X+Y=0)=P(0,0)=0.3

d) P(X + Y <= 1)

P(X+Y \leq 1)=P(0,0)+P(0,1)+P(1,0)\\\\P(X+Y \leq 1)=0.3+0.05+0.18=0.53

5 0
3 years ago
2x minus y equals 6, x plus y equals negative 3
kap26 [50]

Answer:

y=-4, x=1

Step-by-step explanation:

2x-y=6                  x+y=-3

2(-3-y)-y=6            x=-3-y

-6-2y-y=6              x=-3+4

-3y=12                    x=1

y=-4

8 0
3 years ago
PLEASE HURRY WILL GIVE BRAINLIEST A truck can be rented from Company A for $90 a day plus $0.30 per mile. Company B charges $70
rjkz [21]

Answer:

  40 miles a day

Step-by-step explanation:

The difference in fixed charge is $20; the difference in mileage charge is $0.50 per mile. So it will take $20/$0.50 = 40 miles for the extra mileage cost to eat up the savings in fixed cost. At that mileage, both companies will charge the same amount:

  A: 90 + 0.30·40 = 102

  B: 70 + 0.80·40 = 102

4 0
3 years ago
Please help me and we should use laws of exponents​
elena55 [62]

Answer:

3.b

(\frac{8}{3})^{2x+1} *(\frac{8}{3})^{5} =(\frac{8}{3}) ^{x+2}\\\\(\frac{8}{3})^{2x+1 +5} =(\frac{8}{3}) ^{x+2}\\\\\\2x +6 = x+2\\x = -4

i hope question 3.a. is 5^x ÷ 5^-3 = 5^5

3.a.

\frac{5^x}{5^{-3}} = 5^5\\\\5^ {x+3} = 5^5\\\\x+3 = 5\\x =2

6 0
3 years ago
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