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postnew [5]
3 years ago
6

Find the value of the variable

Mathematics
1 answer:
WINSTONCH [101]3 years ago
3 0
Which variable are you talking about? In this question x is 4 and y is 5.

Hope this helped!

Good Luck!
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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
Lady bird [3.3K]

Answer:14

Step-by-step explanation:

Please be certain to use " ^ " to denote exponentiation:

3x^2 + 4x – 5, 7x^2 + x + 9, 4x^2 - 3x

First, perform this subtraction:

 7x2 + x + 9

-(3x2 + 4x – 5)

-----------------------

 4x^2 - 3x + 14

Next, subtract 4x^2 - 3x from the above result:

 4x^2 - 3x + 14

-(4x^2 - 3x)

------------------------

                    14 (answer)

4 0
4 years ago
Solve for.
tigry1 [53]

Answer:

The answer for 5x - 4 > 12 is B

Step-by-step explanation:

8 0
3 years ago
En un avion viajan 120 personas de las cuales
Rzqust [24]
2/3(120) = 240/3 = 80 do not drink
4/5(120) = 480/5 = 96 do not smoke
72 do not smoke or drink

96 - 72 = 24 do not smoke
80 - 72 = 8 do not drink
72 do not do either

120 - (24 + 8 + 72) = 120 - 104 = 16 drink and smoke
4 0
4 years ago
When a certain number x is multiplied by 3 and then add 4. The result is 19
rewona [7]

Hey there! I'm happy to help!

Here is our equation.

3x+4=19

We subtract 4 from both sides.

3x=15

We divide both sides by 3.

x=5.

Have a wonderful day! :D

8 0
4 years ago
Two mechanics Worked on a car The first mechanic charge $55 per hour The second mechanic charge $80 per hour the mechanics work
Tems11 [23]

a = hours worked by the first mechanic

b = hours worked by the second mechanic.

since the first mechanic charges $55 per hour, then for "a" hours that'd be a total of 55*a or 55a, likewise, for the second mechanic that'd be a total charge of 80*b or 80b.

we know all hours combined are 15, so then a + b = 15.

we also know that all charges combined are $950, so 55a + 80b = 950.

\bf \begin{cases} a+b=15\\ \boxed{b}=15-a\\ \cline{1-1} 55a+80b=950 \end{cases}\qquad \qquad \stackrel{\textit{substituting on the 2nd equation}}{55a+80\left( \boxed{15-a} \right)=950} \\\\\\ 55a+1200-80a=950\implies -25a+1200=950\implies -25a=-250 \\\\\\ a=\cfrac{-250}{-25}\implies \blacktriangleright a = 10\blacktriangleleft \\\\\\ \stackrel{\textit{since we know that}}{b=15-a\implies }b=15-10\implies \blacktriangleright b=5 \blacktriangleleft

5 0
3 years ago
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