What is 5x+2-4x+3 please I need help

Neurons are cells in the nervous system that process and transmit information . And average neuron is about 5 • 10^negative 6 me

mrs_skeptik [129]

Since this is about finding the relative value of one parameter to another, our approach of solving this problem is by finding the ratio. In this way, we can compare the degree of their difference.

Ratio = Diameter of ball/Diameter of neuron
Ratio = 0.04 m/5×10⁻⁶ m
Ratio = 8,000
Therefore, the tennis ball is 8,000 times larger than the neuron,

8 0

3 years ago

Read 2 more answers

A building is 1450ft tall. How many meters tall is the building ? Use the fact that 1m = 3.28ft

Mamont248 [21]

Answer:

441.96

Step-by-step explanation: divide 1450 by 3.28

5 0

3 years ago

When asked to rewrite the expression (x3 + 2x? – x)-(-x3 + 2x2 + 6), Denise made a mistake. She did not get the correct answer,

DanielleElmas [232]

Answer:

She rewrote the problem without parentheses: x3+ 2x2 - x + x3 – 2x2 +6

Step-by-step explanation:

It looks like she didn't fully distribute the -

(x3 + 2x2 - x)-(-x3 + 2x2 + 6) :Original

x3+ 2x2 - x + x3 – 2x2 +6 :Changed

~

(x3 + 2x2 - x)-(-x3 + 2x2 + 6)

x3 + 2x2 - x + x3 - 2x2 - 6

x3 + x3 + 2x2 - 2x2 -x - 6

2x3-x-6

I hope this helps ^-^

3 0

3 years ago

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago

QUESTION 2 Which graph could be used to represent a non-proportional situation?

madreJ [45]

The one that doesn’t go through the origin

6 0

3 years ago