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Vitek1552 [10]
3 years ago
10

Grace claims that the interquartile range of a data set is never equal to its range. Which type of set can be used to prove or d

isprove her claim?
A. A set consisting of identical elements will prove her claim.
B. A set consisting of unequal elements will prove her claim.
C. A set consisting of identical elements will disprove her claim.
D. A set consisting of unequal elements will disprove her claim.
Mathematics
2 answers:
ioda3 years ago
6 0
It's either C, or D but I believe it's C.
ohaa [14]3 years ago
6 0

C is correct......................................

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Answer:

  5 minutes; 60 gallons

Step-by-step explanation:

The volume in tank A is initially 35 gallons. Its rate of change is 5 gallons per minute. The equation for volume can be written as ...

  y = 35 +5x . . . . . . where y is gallons, and x is minutes

The volume in tank B is initially 100 gallons. Its rate of change is -8 gallons per minute. The equation for volume can be written as ...

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We want to find the values of x and y such that both are the same for both tanks.

  35 +5x = y = 100 -8x

  13x = 65 . . . . . . . . add 8x-65 to both sides of the equation

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Both tanks will hold 60 gallons after 5 minutes.

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3 years ago
Trey deposits 5000 into an account that pays simple interest at an annual rate of 2%. he does not make any more deposits. he mak
SOVA2 [1]

The simple interest Trey earns if he makes no additional deposit or withdrawal for a period of 6 years is 600

<h3>How to calculate simple interest?</h3>

  • Principal = 5,000

  • Rate = 2%

= 2/100

= 0.02

  • Time = 6 years

Simple interest = principal × rate × time

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Therefore, the simple interest Trey earns if he makes no additional deposit or withdrawal for a period of 6 years is 600

Learn more about simple interest:

brainly.com/question/20690803

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Check the picture below.

so the perimeter of the polygon is the sum of all its sides, namely, AB + BC + CD + DA.

now, let's check how long each side is,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&A&(~{{ -6}} &,&{{ -4}}~) &#10;%  (c,d)&#10;&B&(~{{ -3}} &,&{{ 6}}~)&#10;\end{array}&#10;\\\\\\&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\&#10;-------------------------------\\\\&#10;AB=\sqrt{[-3-(-6)]^2+[6-(-4)]^2}&#10;\\\\\\&#10;AB=\sqrt{(-3+6)^2+(6+4)^2}&#10;\\\\\\&#10;AB=\sqrt{3^2+10^2}\implies \boxed{AB=\sqrt{109}}\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&B&(~{{ -3}} &,&{{6}}~) &#10;%  (c,d)&#10;&C&(~{{ 4}} &,&{{ 0}}~)&#10;\end{array}&#10;\\\\&#10;-------------------------------\\\\&#10;BC=\sqrt{[4-(-3)]^2+[0-6]^2}\implies BC=\sqrt{(4+3)^2+(0-6)^2}&#10;\\\\\\&#10;BC=\sqrt{7^2+(-6)^2}\implies \boxed{BC=\sqrt{85}}\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&C&(~{{ 4}} &,&{{0}}~) &#10;%  (c,d)&#10;&D&(~{{ 2}} &,&{{ -1}}~)&#10;\end{array}&#10;\\\\&#10;-------------------------------\\\\&#10;CD=\sqrt{(2-4)^2+(-1-0)^2}\implies CD=\sqrt{(-2)^2+(-1)^2}&#10;\\\\\\&#10;\boxed{CD=\sqrt{5}}\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&D(~{{ 2}} &,&{{-1}}~) &#10;%  (c,d)&#10;&A&(~{{ -6}} &,&{{ -4}}~)&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;DA=\sqrt{[-6-2]^2+[-4-(-1)]^2}\\\\\\ DA=\sqrt{(-6-2)^2+(-4+1)^2}&#10;\\\\\\&#10;DA=\sqrt{(-8)^2+(-3)^2}\implies \boxed{DA=\sqrt{73}}

sum those sides up, and that's the perimeter of the polygon.

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