The price per ounce of a bag of chips is 0.19 what is the cost c, of a 16 ounce bag of chips write and equation and then solve

A TV station claims that 38% of the 6:00 - 7:00 pm viewing audience watches its evening news program. A consumer group believes

Elena L [17]

Answer:

$z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374$

$p_v =P(Z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .

Step-by-step explanation:

1) Data given and notation

n=830 represent the random sample taken

X=282 represent the people that regularly watch the TV station’s news program

$\hat p=\frac{282}{830}=0.340$ estimated proportion of people that regularly watch the TV station’s news program

$p_o=0.38$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.38:

Null hypothesis: $p\geq 0.38$

Alternative hypothesis: $p < 0.38$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .

3 0

2 years ago

Convertir 675 Faren a Kelvin (Con ecuaciones porfavor)

alexandr1967 [171]

Answer:

<em>(675°F − 32) × 5/9 + 273.15 = 630.372K </em>

Hope it's right if not so sorry :)

5 0

2 years ago

Dimensions of a prism has a scale factor of 7/4 how will this affect surface area<br><br> Plz help

Margaret [11]

The surface area will increase by a factor of 49/16

6 0

3 years ago

Help with this please

Paha777 [63]

I think it is B
hope this helps

6 0

2 years ago

In a factory, 3.25% of the jars of peanut butter produced contains less peanut butter than is advertised on the label. The facto

marshall27 [118]

Answer:

936 jars of peanut butter contain less peanut butter than usual.

Step-by-step explanation:

1. First, we need to find how many jars of peanut butter that contain less peanut butter than advertised are produced every hour.

The factory produces 1200 jars of peanut butter every hour

3.25% of those jars have less peanut butter than advertised

So: multiply $(1200*.0325)$ (the decimal form of the percent) to find the amount of peanut butter jars that contain less peanut butter than advertised.

$(1200*.0325) = 39$

So the factory produces 39 jars of peanut butter that contain less peanut butter than advertised.

2. Second, we need to find how many jars of peanut butter that contain less peanut butter than advertised in three 8 hour work days.

Lets add these work days together to find the total amount of hours: $(8 + 8 + 8) = 24$

So: three 8 hour work days totals to 24 hours

Since the factory produces 39 jars of peanut butter that contain less peanut butter than advertised per hour. Multiply $(24 * 39)$ to find the total amount of jars produced in three 8 hour work days.

$(24 *39) = 936$

A total of 936 peanut butter jars are produced in three 8 hour work days that contain less peanut butter than advertised.

3. If you want to double check your work do the following.

Since the factory produces 1200 jars an hour and 24 hours total three 8 hour work days. Multiply $(1200*24) = 28800$

So there is a total of 28800 jars produced in three 8 hour work days.

Then you can multiply 28800 by 3.25% of jars that contain less peanut butter to find the total amount of peanut butter jars that contain less peanut butter in three 8 hour work days.

$(28800 * .0325) = 936$

7 0

2 years ago