If anything is in parentheses do that first, however if there isn’t you always do exponents next so evaluate 6 squared
Hope this helps!!
Answer:
The value of x will be 8
Step-by-step explanation:
We have given that ![2\sqrt{x}=32](https://tex.z-dn.net/?f=2%5Csqrt%7Bx%7D%3D32)
We have to find the value of x
As ![2\sqrt{x}=32](https://tex.z-dn.net/?f=2%5Csqrt%7Bx%7D%3D32)
For finding the value of x we have to square both side
On squaring both side
We done squaring both side for easy simplification
![4x=32](https://tex.z-dn.net/?f=4x%3D32)
So x = 8
So the value of x will be 8
So answer will be 8
Answer:
The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground.
Step-by-step explanation: