All categories

3 years ago

How do I do this puzzle

Mathematics

1 answer:

irga5000 [103]3 years ago

7 0

It's just saying that you need to find the volume and surface area and then write them in the designated area, which will be on the side or the bottom.

After doing this for all of them, you have to find two matching numbers and put them together on the same side.

For example:
When you got 722, you can just find another square that might say 722 on square area or volume, then just put the numbers together on the same side.

I don't know if this helped but I hope it did!

You might be interested in

There are 15 boys and 16 girls in a class room. Write the following ratio: boys to girls

aalyn [17]

Answer:

93.75% i hope that helps

Step-by-step explanation:

7 0

3 years ago

Cuántas diagonales tendría una figura de 8 lados?

Oduvanchick [21]

Answer: 20 diagonales

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Evaluate. 9.75 + 4.625 + (-9.75) + 2.6=?

marusya05 [52]

The answer would be 7.225.

4 0

3 years ago

Read 2 more answers

Please answer asap. thank you

DochEvi [55]

Answer:

7 Seconds

Step-by-step explanation:

Bruhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

8 0

3 years ago

Read 2 more answers

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago