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slava [35]
3 years ago
10

The excavation for a house and the trucks to carry away the material have the dimensions shown. About how many level truck loads

are necessary to remove all the dirt? The truck is 5.0 for the length 2.0 for the height 3.0 for the side base The house is 4.0 for the height 14.5 for the length and 11.0 for the side base 100 points !!!!! and brainlist
Mathematics
1 answer:
Inessa05 [86]3 years ago
8 0

Answer:

<h3>This means that about 21 level truck loads are necessary to remove all dirts.</h3>

Step-by-step explanation:

To get the number of level truck loads needed to remove all the dirts in the house, first we need to calculate volume of the truck and the house.

Volume of truck = Length * Breadth * Height

If the truck is 5.0 for the length 2.0 for the height 3.0 for the side base;

Volume of the truck = 5*2*3

Volume of truck = 30

For the house;

Volume of house = Length * Breadth * Height

If the house is 4.0 for the height 14.5 for the length and 11.0 for the side base, then

Volume of the house = 4*14.5*11 = 638

Number of level truck loads needed to remove all the dirts = Volume of house/Volume of the truck = 638/30 ≈ 21.3

This means that about 21 level truck loads are necessary to remove all dirts.

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How do you decide where to shade an inequality whose boundary does not go through the origin?
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Answer:

Step-by-step explanation:

basically, you have to look at the inequality. it is the same all around. so if the inequality has less than or equal too, or greater than or equal too, you need to have a thick solid line representing your function. if it is just less than or greater than, use a dotted line. to determine whether the shading goes above or below, you look at the in equality. greater than is above, and less than is below

4 0
3 years ago
Natalie is an expert archer. The following table shows her scores (points) based on the number of targets she hit.
Alekssandra [29.7K]

Answer:

yes the anwer is A

Step-by-step explanation:

5 0
3 years ago
Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with μ=10
Tju [1.3M]

Answer: 0.8238

Step-by-step explanation:

Given : Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with \mu=106 and \sigma=15.

Let x denotes the scores on a certain intelligence test for children between ages 13 and 15 years.

Then, the proportion of children aged 13 to 15 years old have scores on this test above 92 will be :-

P(x>92)=1-P(x\leq92)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{92-106}{15})\\\\=1-P(z\leq })\\\\=1-P(z\leq-0.93)=1-(1-P(z\leq0.93))\ \ [\because\ P(Z\leq -z)=1-P(Z\leq z)]\\\\=P(z\leq0.93)=0.8238\ \ [\text{By using z-value table.}]

Hence, the proportion of children aged 13 to 15 years old have scores on this test above 92 = 0.8238

4 0
3 years ago
6. Interest is compounded semianually. Find the amount in the account after the given time.
patriot [66]

The amount in the account after the given time if compounded semiannually is $1104.2

<h3>Compound interest </h3>

Interest is any amount added on a sum of money over a period of time. The formula for calculating the compound interest is:

A = P(1+r/n)^nt

Given

P = $1000

rate r = 0.05

time =3years

n = 2

Substitute

A = 1000(1 + 0.05/3)^3(2)
A= 1000(1.1042)
A = $1104.2

Hence the amount in the account after the given time if compounded semianually is $1104.2

Learn more on compound interest here: brainly.com/question/24924853

#SPJ1

5 0
2 years ago
Lana finished the race in 13.2 seconds . If 84 other girls ran in the event, approximately how many runners did she beat?
BabaBlast [244]

Complete question :

The 100m dah times in the girl's track meet were normally distributed with a mean of 13 seconds and a standard deviation of 0.3 seconds.

Lana finished the race in 13.2 seconds . If 84 other girls ran in the event, approximately how many runners did she beat?

Answer:

21 runners

Step-by-step explanation:

Mean, μ = 13 seconds

Standard deviation, σ = 0.3

Lana's race time = 13.2

We find the proportion of runners who had race time above 13.2 ;

Proportion of who had race tune above 13.2

P(x > 13.2)

Obtain the Zscore

Zscore = (x - μ) / σ

Z = (13.2 - 13) / 0.3

Zscore = 0.2 / 0.3 = 0.6667

P(Z > 0.6667) = 0.25239 (Z probability calculator)

This is about 0.25239 * 100 = 25.24% = 25% (nearest percent)

Hence, Number of runners Lana beat = 25% of total runners ;

0.25 * 84 = 21

Hence, Lana beat about 21 runners

6 0
3 years ago
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