From the cars parked in the lot he will earn (40)($10)=$400, but he will need to pay $50 for the rent. Thus his total $ earned will be $400-$50=$350.
134,500 rounded to the nearest ten thousandth is about 130,000. :)
Hey next time use your calculator, if you can.
Since these problems are using this equation :
we can derive into this immediately.
Q1: 525 (Try it, don't copy, it's not nice ;) ).
Q2: 865.28
Q3: By using logs: 0.0566 years. (I'm not sure on that one...) Sry
Answer:
1, 5, 2, 4, 3, 7, 6
Step-by-step explanation:
After dividing by the leading coefficient, each equation can be put into the form ...
x² + y² + ax +by +c = 0
Subtracting c and separately completing the square for x-terms and y-terms, we get ...
x² + ax + (a/2)² + y² + by + (b/2)² = -c + (a/2)² + (b/2)²
(x +a/2)² + (y +b/2)² = r² = (a/2)² + (b/2)² -c . . . . . rewrite in standard form
Ordering by the square of the radius length will match the ordering by radius length, so we just need to compute (a/2)² +(b/2)² -c for each given equation. I find it convenient to let a calculator or spreadsheet do this calculation (see attached).
In the order the equations are given, the square of the radius is ...
3, 18, 45, 23, 5, 117, 46
So the order of the equations from smallest radius to largest is ...
1, 5, 2, 4, 3, 7, 6
Answer: Length of fence along the diagonal is 28.3 feet.
Step-by-step explanation:
Since we have given that
The Blackburn family has a square field ,
Area of square = 40000 ft square
As we know the formula,
Area of square = Side x Side
40000 = slide

20 ft = Side
But Blackburn wants to put a fence diagonally through the field ,
As we know the formula for "Diagonal of side" i.e.
Diagonal of square 
Diagonal of square 20
So,
Length of fence along the diagonal = 20 x 1.41 = 28.3
Hence, length of fence along the diagonal is 28.3 feet.
Hope this helps!