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Alexeev081 [22]
3 years ago
10

Add the expressions. (⎯⎯)+(⎯+)

Mathematics
2 answers:
maxonik [38]3 years ago
5 0

Answer:

i think +- but im not sure

Step-by-step explanation:

murzikaleks [220]3 years ago
4 0
Uh confusion is here.
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Ron charges $10 to park a car in his parking lot. He pays $50 per day to rent the lot. If 40 cars park in his lot during the day
jolli1 [7]
From the cars parked in the lot he will earn (40)($10)=$400, but he will need to pay $50 for the rent. Thus his total $ earned will be $400-$50=$350.
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3 years ago
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What is 134,500 rounded to the nearest ten thousand
Alexeev081 [22]
134,500 rounded to the nearest ten thousandth is about 130,000. :)
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3 years ago
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PLZZZ HELP, i have limited time and i will give brainliest. Q1 Selena has placed $500 in an account that pays simple interest of
Sergio039 [100]

Hey next time use your calculator, if you can.

Since these problems are using this equation : A(mount) = P(rinciple) * ( 1 + R(ate) ^ {t(ime)} ) we can derive into this immediately.

Q1: 525 (Try it, don't copy, it's not nice ;) ).

Q2: 865.28

Q3: By using logs: 0.0566 years. (I'm not sure on that one...) Sry

6 0
3 years ago
HELP!!!!!
SCORPION-xisa [38]

Answer:

  1, 5, 2, 4, 3, 7, 6

Step-by-step explanation:

After dividing by the leading coefficient, each equation can be put into the form ...

  x² + y² + ax +by +c = 0

Subtracting c and separately completing the square for x-terms and y-terms, we get ...

  x² + ax + (a/2)² + y² + by + (b/2)² = -c + (a/2)² + (b/2)²

  (x +a/2)² + (y +b/2)² = r² = (a/2)² + (b/2)² -c . . . . . rewrite in standard form

Ordering by the square of the radius length will match the ordering by radius length, so we just need to compute (a/2)² +(b/2)² -c for each given equation. I find it convenient to let a calculator or spreadsheet do this calculation (see attached).

In the order the equations are given, the square of the radius is ...

  3, 18, 45, 23, 5, 117, 46

So the order of the equations from smallest radius to largest is ...

  1, 5, 2, 4, 3, 7, 6

5 0
3 years ago
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The Blackburn family has a square fold where they keep their cattle.The area of the field is 40,000ft square, and Mr. Blackburn
grandymaker [24]

Answer: Length of fence along the diagonal is 28.3 feet.

Step-by-step explanation:

Since we have given that

The Blackburn family has a square field ,

Area of square = 40000 ft square

As we know the formula,

Area of square = Side x Side

40000 = slide{2}

\sqrt 40000\\

20 ft = Side

But Blackburn wants to put a fence diagonally through the field ,

As we know the formula for "Diagonal of side" i.e.

Diagonal of square \sqrt2Slide

Diagonal of square 20\sqrt2

So,

Length of fence along the diagonal = 20 x 1.41 = 28.3

Hence, length of fence along the diagonal is 28.3 feet.

Hope this helps!

7 0
4 years ago
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