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Maurinko [17]
3 years ago
7

Evaluate log416 -2 1/2 2

Mathematics
1 answer:
krok68 [10]3 years ago
5 0

16 = 4²

So, by the definition of logarithms

\log_4{16}=2

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How many solutions does the following system have?<br> 2x- 4y = 11<br> -2x + 4y = -10
rosijanka [135]

Answer:

This system has no solution

Step-by-step explanation:

-(11+4y)+4y=-10

no solution

6 0
3 years ago
Read 2 more answers
8x^2+18x-5=0 find the discriminant
Shalnov [3]
The formula for the discriminant is the square root of b^2 - 4ac

8x^2+18x-5= 0

a = 8, b=18, c= -5

Square root of 324 +160

Square root of 484 = 22                The discriminant is 22


7 0
3 years ago
The decimal equivalent 3/5 is a repeating decimal true or false?
Svetlanka [38]

Answer: false

Step-by-step explanation:

3/5 in a decimal is 0.6. overall 0.6 is not an repeating decimal.

4 0
3 years ago
Need help with this ignore what a put in the box it isn’t right
Zarrin [17]

f=6cm\\g=8cm

Why?

The first thing we need to do is find the area of the triangle, we can to that by subtracting the area of ABCD from ACBE, then, we can use the formulas to calculate the area for both triangle and rectangle to find "f" and "g".

Calculating we have:

TriangleArea=ABCE-ABCD\\\\TriangleArea=60cm^{2}-48cm^{2}=12cm^{2}

Now, we can calculate "f" by using the formula to calculate the area of the triangle:

TriangleArea=\frac{b*h}{2}\\\\TriangleArea=\frac{f*4cm}{2}\\\\12cm^{2}*2=f*4cm\\\\\frac{24cm^{2}}{4cm}=f\\\\f=6cm

Now, finding "g" by using the formula to calculate the area of the rectangle, we have:

RectangleArea=ABCD\\\\ABCD=Base*Height\\\\48cm^{2}=base*6cm\\\\base=g=\frac{48cm^{2}}{6cm}=8cm

Hence, we have that:

f=6cm\\g=8cm

Have a nice day!

8 0
3 years ago
The heights of apricot trees in an orchard are approximated by a normal distribution model with a mean of 18 feet and a standard
Ulleksa [173]

Answer:

0.9544

Step-by-step explanation:

We are given that mean=18 and standard deviation=1 and we have to find P(16<X<20).

P(16<X<20)=P(z1<Z<z2)

z1=(x1-mean)/standard deviation

z1=(16-18)/1=-2

z2=(x2-mean)/standard deviation

z2=(20-18)/1=2

P(16<X<20)=P(z1<Z<z2)=P(-2<Z<2)

P(16<X<20)=P(-2<Z<0)+P(0<Z<2)

P(16<X<20)=0.4772+0.4772=0.9544

The probability that the height of a tree is between 16 and 20 feet is 95.44%

5 0
3 years ago
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