The school that Stefan goes to is selling tickets to a choral performance on the first day of ticket sales the school sold three
1 answer:
The price of 1 senior citizen ticket is $ 8
<em><u>Solution:</u></em>
Let "x" be the price of 1 senior citizen ticket
Let "y" be the price of 1 child ticket
<em><u>The school sold three senior citizen tickets and one child ticket for a total of $38</u></em>
Therefore, we frame a equation as:
three senior citizen tickets x price of 1 senior citizen ticket + one child ticket x price of 1 child ticket = 38
3x + y = 38 --------- eqn 1
<em><u>The school took an $52 on the second day by selling three senior citizen tickets and two child tickets</u></em>
Therefore, we frame a equation as:
three senior citizen tickets x price of 1 senior citizen ticket + two child ticket x price of 1 child ticket = 52
3x + 2y = 52 ---------- eqn 2
<em><u>Solve eqn 1 and eqn 2</u></em>
<em><u>Subtract eqn 1 from eqn 2</u></em>
3x + 2y - 3x - y = 52 - 38
<h3>y = 14</h3><em><u>Substitute y = 14 in eqn 1</u></em>
3x + y = 38
3x + 14 = 38
3x = 24
<h3>x = 8</h3>Thus the price of 1 senior citizen ticket is $ 8
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Answer:
Option (B). Perimeter of the quadrilateral ABCD= 14.6 units
Step-by-step explanation:
From the figure attached,
Coordinates of the vertices are A(3, 5), B(1, 3), C(3, -1), D(5, 3).
Length of AB =
=
=
= 2.83 units
Length of AD =
=
= 2.83 units
Length of BC =
=
= 4.47 units
Length of DC =
=
= 4.47 units
Perimeter of the quadrilateral = AB + AD + DC + BC
= 2.83 + 2.83 + 4.47 + 4.47
= 14.6 units
Option (B) is the answer.
I added a picture with it for you. I suggest that before this becomes an issue you take some time and study box and whisker plots, because they tend to show up on a lot of standardized math tests.
