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qwelly [4]
3 years ago
15

Where would we find the point -10, 0

Mathematics
1 answer:
mr Goodwill [35]3 years ago
6 0
What do you mean by that?
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In HIJ, the measure of J=90°, HI = 65 feet, and IJ = 31 feet. Find the measure of
o-na [289]

Answer:

28.5

Step-by-step explanation:

5 0
3 years ago
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F(x)=tgx*ctgx.calculați derivata funcției
Marina86 [1]
Nota: am folosit Google Translate așa că sper sensul nu se pierde în traducere<span>

Sunt presupunând că t, g, și c sunt constante

</span>simplifica

f(x)=cg²t²x²

amintiți-vă că derivitive de af (x), în cazul în care a este o constantă este un lucru ori mai mare decât derivitve lui f (x)

f(x)=cg²t²(x²)

<span>Amintiti-va: derivitive lui x^n este nx^{n-1}</span>
<span>

</span>
<span>f'(x)=cg²t²(2x¹)
f'(x)=cg²t²(2x)
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5 0
3 years ago
Please, help me with this one! Y= 37,39,51
wlad13 [49]

Answer:

Step-by-step explanation:

tany=8/10

y=tan^-1 8/10

y=38.65...

therefore y = 39°

Hope this helps!

3 0
3 years ago
The mean weight of 500 college students is 70 kg and the standard deviation is 3 kg. Assuming that the weight is normally distri
Anna71 [15]

Answer: 4.75%.

Step-by-step explanation:

Given: The mean weight (\mu) of 500 college students is 70 kg and the standard deviation(\sigma) is 3 kg.

Let X be the number of students weight over 75 kg.

If the weight is normally distributed, then the probability that students weigh over 75 kg:

P(X>75)=P(\dfrac{X-\mu}{\sigma}>\dfrac{75-70}{3})\\\\=P(z>\dfrac53)\\\\=P(z>1.67)\\\\=1-P(z

Hence, the  percentage of students weigh over 75 kg = 4.75%.

6 0
3 years ago
T object]user: what is the slope of a line that passes through (–4,–13) and (19,11)?
Ray Of Light [21]
<span>Slope is difference in "y" divided by difference in "x"
(–4,–13) (19,11)

slope = (-13 -11) / (-4, -19) = -24 / -23


</span>
8 0
3 years ago
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