Answer:
- 273 mL of 5%
- 117 mL of 15%
Step-by-step explanation:
Let q represent the quantity of 15% dressing used. Then the amount of 5% dressing is (390 -q). The amount of vinegar in the mix is ...
0.15q + 0.05(390 -q) = 0.08(390)
0.10q = 31.2 -19.5 = 11.7 . . . . . . subtract 0.05(390) and simplify
q = 117 . . . . . . . . . . . . . . . . . . multiply by 10
390-q = 273
The chef should use 273 mL of the first brand (5% vinegar) and 117 mL of the second brand (15% vinegar).
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<em>Additional comment</em>
You may have noticed that the value of q is (0.08 -0.05)/(0.10 -0.05)×390. The fraction of the mix that is the highest contributor is the ratio of the difference between the mix value and least contributor, divided by the difference between the contributors: (8-5)/(15-5) = 3/10, the fraction that is 15% vinegar. This is the generic solution to mixture problems.
<span>b – 2a – c
= 9 - 2(-3) - (-6)
= 9 + 6 + 6
= 21
answer
21</span>
Number 11
Since the auditorium can hold 600 and the student body will be divide by four parts
The answer is
x ≤ 2400
Answer: B
Step-by-step explanation: 7/8 * 3 = 2 5/8 :)
Answer:
- <u><em>The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.</em></u>
Explanation:
Name the variables and build a system of two equations with two unknowns.
<u>1. Variable r</u>: cost of one rose bush
<u>2. Variable g</u>: cost of one bunch of ornamental grass.
<u>3. First equation</u>:
- Shreya spent $68 on 4 rose bushes and 4 bunches of ornamental grass.
4r + 4g = 68
<u>4. Second equation</u>:
- Beth spent $115 on 11 rose bushes and 2 bunches of ornaments grass.
<u>5. System of equations</u>:
- 11r + 2g = 115 equation 2
<u>6. Solve the system</u>
a) Divide the equation 1 by 2:
- 11r + 2g = 115 equation 2
b) Subtract equation 1a from equation 2:
c) Substitute the value of r into the equation 1a:
<u>7. Conclusion</u>:
The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.
