Considering the reaction stoichiometry, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.
<h3 /><h3>Reaction stoichiometry</h3>
The balanced reaction is:
3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Cu: 3 moles
- HNO₃: 8 moles
- Cu(NO₃)₂: 3 moles
- NO: 2 moles
- H₂O: 4 moles
<h3>Amount of moles of NO produced</h3>
It is possible to determine the the amount of moles of NO produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 2 moles of NO, if 27 moles of HNO₃ react how many moles of NO will be formed?

<u><em>amount of moles of NO= 6.75 moles</em></u>
In summary, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.
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<u>Answer:</u> The final temperature of water is 38.5°C
<u>Explanation:</u>
To calculate the amount of heat released or absorbed, we use the equation:

where,
q = heat absorbed = 1.506 kJ = 1506 J (Conversion factor: 1 kJ = 1000 J)
m = mass of water = 30 g
c = specific heat capacity of water = 4.184 Jl/g.°C
= change in temperature = 
Putting values in above equation, we get:

Hence, the final temperature of water is 38.5°C
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