The two
Esters along with starting materials are shown below. The missing reagents ate shown in Blue encircled in red box. First reaction is carried out in acid which increases the reactivity of carboxylic acid (
electrophilicity odf carbonyl carbon). And second reaction is carried out in the presence of Base, which increases the
Nucleophilicity of nucleophile i.e. Alcohols.
The activation energy Ea can be related to rate constant (k) at temperature (T) through the equation:
ln(k2/k1) = Ea/R[1/T1 - 1/T2]
where :
k1 is the rate constant at temperature T1
k2 is the rate constant at temperature T2
R = gas constant = 8.314 J/K-mol
Given data:
k1 = 0.543 s-1; T1 = 25 C = 25+273 = 298 K
k2 = 6.47 s-1; T = 47 C = 47+273 = 320 K
ln(6.47/0.543) = Ea/8.314 [1/298 - 1/320]
2.478 = 2.774 *10^-5 Ea
Ea = 0.8934*10^5 J = 89.3 kJ
A: 6 moles
You have to find the molar mass and then multiply
When heating lithium carbonate (Li2CO3), it will dissociate to Li2O and Co2. So the balanced chemical equation of this reaction is Li2CO3 = Li2O + CO2.