Answer:

Explanation:
It is given that,
Length of the coil, l = 3 cm = 0.03 m
Area of cross section of the coil, 
Number of turns in the coil, N = 300
inductance of the coil is


So, the inductance of the coil is 1.88× 10⁻⁴H
Answer:
The extent to which it would stretch is 
Explanation:
From the question we are told that
The initial length is 
The area is 
The Young modulus of the steel is 
The tension is 
The Young modulus is mathematically represented as

Where
is the stress which is mathematically represented as
Substituting values
And e is the strain which is mathematically represented as

Where
The extension of the steel string
Substituting these into the equation above

Substituting values



Answer:
216.39 N/m
Explanation:
F = 64.7 N
x = 0.299 m
Plug those values into Hooke's Law:
F = kx
64.7 N = k(0.299 m)
---> k = 216.39 N/m
Frictional force from the friction caused between the course pavement and the rubber tire. It wears down the tire.