Answer:
33 N
Explanation:
v = Velocity of fluid = 8+2 = 10 m/s
= Density of fluid = 1.2 kg/m³
C = Coefficient of drag = 1.1
A = Cross sectional area = 0.5 m²
Drag force is given by

The drag force on the athlete is 33 N
K (Q1) (Q2)/d^2 =
k : coulumb constant
Q1 : Charge on object 1
Q2 : Charge on object 2
d : distance between two charged object
Answer:

Explanation:
As we know that Far sighted person has near point shifted to 80 cm distance
so he is able to see the object 80 cm
now the distance of lens from eye is 2 cm
and the person want to see the objects at distance 10 cm
so here the image distance from lens is 80 cm and the object distance from lens is 8 cm
now from lens formula we have



If i thought about this properly the answer is b
I would say The answer is false