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4 years ago

Can we use a clinical thermometer to measure the temperature of a candle flame

1 answer:

3 0

In theory, yes. The 2 problems are the materials used for clinical thermometers, & the temperature capacity of the clinical thermometer. If anything, change the material & extend the measurement threshold. At that point, it wouldn´t be used for clinical garbage anymore.

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Select all of the answers that apply. Jenna dives 20meters into the ocean. How much pressure does she feel?

Triss [41]

Use the formula dgh + p atm

d is density g is gravitational field strength h heigh or depth and p atm is atmospheric pressure

1000 x 10 x 20 + 100000 = 300000

almost 300,000 pascal

4 0

4 years ago

3. How do you think a hot air balloon works?

tiny-mole [99]

Answer:hot air

Explanation:Hot air goes up, so when you put it in a hot air balloon fire is placed at the oppening to creat hot air and lift the balloon! :)

5 0

3 years ago

1)why do we get electric shock while holding a live wire barefooted and not when wearing rubber shoes?

katrin2010 [14]

Electricity is always going to take the path of least resistance to ground. The rubber in your shoes is not a conductor of electricity, therefore you are not completing the circuit and you don't get shocked. Your bare feet, on the other hand ARE conductors of electricity, so when you hold the wire, you complete the circuit and become the path of least resistance to ground... ZAP!

5 0

3 years ago

A car generator turns at 400 rpm (revolutions per minute) when the engine is idling. It has a rectangular coil with 300 turns of

Sav [38]

The field strength needed to produce a 24.0 V peak emf is 0.73T.

To find the answer, we need to know about the expression of emf.

What's the expression of peak emf produced in a rotating rectangular loops?

The peak emf produced in a rotating loops= N×B×A×w
N= no. of turns of the loop, B= magnetic field, A= area of loop and w= angular frequency
So, B = emf/(N×A×w)

<h3>What's the magnetic field applied to the loop, when rectangular coil with 300 turns of dimensions 5.00 cm by 5.22 cm rotates at 400 rpm produce a 24.0 V peak emf?</h3>

N= 300, A= 5cm × 5.22cm = 0.05m × 0.0522m = 0.00261 m²
Emf= 24V, w= 2π×400 rpm= 2π×(400rps/60) = 42 rad/s
Now, B= 24/(300×0.00261×42)

B= 24/(300×0.00261×42) = 0.73T

Thus, we can conclude that the magnetic field is 0.73T.

Learn more about the electromagnetic force here:

brainly.com/question/13745767

#SPJ4

6 0

2 years ago

A sheet of metal is 2mm wide 10cm tall and 15cm long. it was 4g. what is the density? <br>

Hoochie [10]

Answer:

Ro = 133 [kg/m³]

Explanation:

In order to solve this problem, we must apply the definition of density, which is defined as the relationship between mass and volume.

$Ro = m/V$

where:

m = mass [kg]

V = volume [m³]

We will convert the units of length to meters and the mass to kilograms.

L = 15 [cm] = 0.15 [m]

t = 2 [mm] = 0.002 [m]

w = 10 [cm] = 0.1 [m]

Now we can find the volume.

$V = 0.15*0.002*0.1\\V = 0.00003 [m^{3} ]$

And the mass m = 4 [gramm] = 0.004 [kg]

$Ro = 0.004/0.00003\\Ro = 133 [kg/m^{3}]$

3 0

3 years ago

Can we use a clinical thermometer to measure the temperature of a candle flame​

Can we use a clinical thermometer to measure the temperature of a candle flame