Answer:
120 ways
Step-by-step explanation:
To solve the question above, we use combination formula:
Where ;
nCr = n! / (n-r)! r!
10C7 = 10! / (10 - 7)! 7!
10C7 = 10! / 3! 7!
10C7 = (10 * 9 * 8) / 3 * 2 * 1
10C7 = 720 / 6
= 120 ways
Answer:
24x^2+112x+120
Step-by-step explanation:
distribute the 2
(6x+10)(4x+12)
foil it
24x^2+112x+120
Answer:
The family would have
of the watermelon for supper.
Step-by-step explanation:
Given:
Amount of watermelon in refrigerator = ![\frac14](https://tex.z-dn.net/?f=%5Cfrac14)
Amount of water melon brought form grocery store =![\frac12](https://tex.z-dn.net/?f=%5Cfrac12)
We need to find the fraction of water melon family have for supper.
Solution:
Now we can say that;
the fraction of water melon family have for supper is equal to sum of Amount of watermelon in refrigerator and Amount of water melon brought form grocery store.
framing in equation form we get;
the fraction of water melon family have for supper = ![\frac14+\frac12](https://tex.z-dn.net/?f=%5Cfrac14%2B%5Cfrac12)
Now taking LCM to make the denominator common we get;
the fraction of water melon family have for supper = ![\frac{1\times1}{4\times1}+\frac{1\times2}{2\times2}=\frac{1}{4}+\frac24](https://tex.z-dn.net/?f=%5Cfrac%7B1%5Ctimes1%7D%7B4%5Ctimes1%7D%2B%5Cfrac%7B1%5Ctimes2%7D%7B2%5Ctimes2%7D%3D%5Cfrac%7B1%7D%7B4%7D%2B%5Cfrac24)
Now denominators are common so we will solve for numerator we get;
the fraction of water melon family have for supper = ![\frac{1+2}{4}=\frac34](https://tex.z-dn.net/?f=%5Cfrac%7B1%2B2%7D%7B4%7D%3D%5Cfrac34)
Hence the family would have
of the watermelon for supper.