AB^2 + BC^2 = AC^2
AB^2 + 6^2 = square root 117^2
AB^2 + 36 = 117
Now subtract 117 from both sides
AB^2 = 81
AB = square root 81 = 9

Therefore AB is 9 cms.
The total of two whole numbers one after another is 33. for example 10 + 11 (two consecutive integers) = 21
Answer:
we need 2 equations to solve by elimination