Pls help answer this soon!!!!!

Mathematics

2 answers:

vladimir1956 [14]3 years ago

7 0

13a) y = 0.45x

13b) 52 * 0.45 = 23.4

13c) I will let u figure this one out

Gemiola [76]3 years ago

4 0

0.45x work: $0.45 per bag (unknown)
$23.40 work: $0.45(52 bags)
$23.40/x work: 0.45(52)/x part / whole <or> is/of

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If g (x) = 3x+7, then which of the following is the solution to g (x) = 1

BabaBlast [244]

Answer:

the answer might be 10 not really sure

4 0

2 years ago

Roberto’s cat weighed 6 3/4 pounds last year.Then the cat gained 1 1/2 pounds.How much does the cat weigh now?

hammer [34]

Add the gain and the last weight together
new weight = 6 3/4 + 1 1/2
or we can write it as
new weight = 6 + 3/4 + 1 + 1/2

Separate whole numbers and fraction
new weight = 6 + 3/4 + 1 + 1/2
new weight = 6 + 1 + 3/4 + 1/2

Simplify the whole numbers
new weight = 6 + 1 + 3/4 + 1/2
new weight = 7 + 3/4 + 1/2

Equalize the denominators of the fraction
new weight = 7 + 3/4 + 1/2
new weight = 7 + 3/4 + 2/4
new weight = 7 + 5/4

Because 5/4 is improper fraction, change it to mixed fraction
new weight = 7 + 5/4
new weight = 7 + 1 1/4
new weight = 7 + 1 + 1/4
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The cat weights 8 1/4 pounds now

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2 years ago

Rearrange the formula A = \pi r ^ ( 2) for r

tatyana61 [14]

Consider re-writing this formula as "A = pi*r^2." The backslash symbol "\" is unnecessary.

If A = pi*r^2, and we wish to solve for r, then divide both sides by pi:

A/pi = r^2

Taking the square root of both sides, sqrt(A/pi) = r (r must be positive in this situation).

3 0

3 years ago

Solve each equation by graphing the related function. If th equation has no real number solution, write no solution. X^2 + 7 = 0

Brrunno [24]

Answer:
The equation x² + 7 = 0 has no solution

Explanation:
1- using graph:
To solve the equation means graphically means to find the x-intercepts.
The attached image shows the graph of the given function.
We can note that there are no x-intercepts. This means that the given function has no real solutions

2- using algebra:
To solve the equation algebraically means to find the values of x that would make the equation equal to zero.
Solving the given equation, we would find that:
x² + 7 = 0
x² = -7
x = <span>± </span>√-7
The square root of a negative number will always give imaginary values. This means that the equation has no real solutions

Hope this helps :)