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3 years ago

What is the domain function ((1,1), {0,0}, (2,-1))

Mathematics

2 answers:

Gre4nikov [31]3 years ago

5 0

The domain is the x values

( 0,1,2)

Molodets [167]3 years ago

4 0

(0,1,2) hope this helps

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.. Find the L.C.M. of (a - 5)(a – 4) and (a + 4)(a – 5)

andrew-mc [135]

A-5 A-5 AND A-4 A-5

A-10 AND A-1

Hope it helps you

3 0

3 years ago

Read 2 more answers

Someone help me plz !!!!!

Mrac [35]

Answer:

£1 = 25 hits

Step-by-step explanation:

Will get the equation is

$\frac{40}{1000} = \frac{1}{x}$

so, X=25

x = What we want to find

4 0

3 years ago

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

Cynthia Besch wants to buy a rug for a room

77julia77 [94]

The length and width of the rug is 20 and 11 feet respectively

The given parameters;

dimension of the room = 19 ft by 28 ft

maximum area of rug she can afford = 220 ft²

For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y

(28-2x)(19-2x)=220

532-94x+4x^2=220

4x^2-94x+312=0

x=39/2,4

For x=39/2, dimensions are negative.

The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11

Thus, the dimensions of the rug should be 20 feet and 11 feet

The area of a rectangle is length times breadth.
Area is the total squares cm occupied by a closed figure.

To learn more about area of a rectangle visit:

brainly.com/question/20693059

#SPJ9

6 0

1 year ago

Identify the equation in slope-intercept form for the line that has the given slope and contains the given point. Slope = −1/2;

taurus [48]

First you need the equation y=mx+b
you plug in x and y do find b the y intercept
-5 = -1/2*4 +b
-5 = -2 + b
b = -3
y = -1/2x-3

6 0

3 years ago